Question

Difficulty: EasyQuadratic Equations and the Quadratic Formula

What are the solutions to the quadratic equation x252x+1=0x^2 - \frac{5}{2}x + 1 = 0?

  1. A
    x=12x = -\frac{1}{2} and x=2x = -2
  2. B
    x=1x = 1 and x=14x = \frac{1}{4}
  3. x=12x = \frac{1}{2} and x=2x = 2Answer
  4. D
    x=54+34ix = \frac{5}{4} + \frac{3}{4}i and x=5434ix = \frac{5}{4} - \frac{3}{4}i
  5. E
    x=34x = \frac{3}{4} and x=34x = -\frac{3}{4}

Answer

The solutions are x=12x = \frac{1}{2} and x=2x = 2.
The correct answer provides the exact solutions to the equation. Multiplying the equation by 22 yields 2x25x+2=02x^2 - 5x + 2 = 0. Factoring this expression gives (2x1)(x2)=0(2x - 1)(x - 2) = 0, which yields the solutions x=12x = \frac{1}{2} and x=2x = 2.

Step-by-Step Solution

1
Multiply the entire equation by 22 to clear the fraction.
2x25x+2=02x^2 - 5x + 2 = 0
Converting the equation to integer coefficients simplifies factoring or applying the quadratic formula.
2
Identify the coefficients aa, bb, and cc to use in the quadratic formula.
a=2a = 2, b=5b = -5, c=2c = 2
These coefficients correspond to the standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0.
3
Calculate the discriminant b24acb^2 - 4ac.
(5)24(2)(2)=2516=9(-5)^2 - 4(2)(2) = 25 - 16 = 9
The discriminant determines the number and type of solutions.
4
Substitute the coefficients and the discriminant into the quadratic formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}.
x=(5)±92(2)=5±34x = \frac{-(-5) \pm \sqrt{9}}{2(2)} = \frac{5 \pm 3}{4}
This formula provides the exact solutions to any quadratic equation.
5
Evaluate the two cases for the plus/minus sign.
x=5+34=2x = \frac{5 + 3}{4} = 2 and x=534=12x = \frac{5 - 3}{4} = \frac{1}{2}
Splitting the formula into positive and negative branches yields the two distinct real roots.

Key Concept

Solving quadratic equations using the quadratic formula
Rate this question