Question

Difficulty: MediumRight Triangle Trigonometry (SOHCAHTOA)

In right triangle PQRPQR, the right angle is located at vertex QQ. The length of leg PQPQ is 3030 centimeters. If sin(P)=817\sin(P) = \frac{8}{17}, what is the length, in centimeters, of leg QRQR?

  1. 1616Answer
  2. B
    24017\frac{240}{17}
  3. C
    1818
  4. D
    3434
  5. E
    2254\frac{225}{4}

Answer

16 centimeters
In right triangle PQRPQR, sin(P)=QRPR=817\sin(P) = \frac{QR}{PR} = \frac{8}{17}. The corresponding cosine ratio is cos(P)=PQPR=1517\cos(P) = \frac{PQ}{PR} = \frac{15}{17}. Given PQ=30PQ = 30, we solve 30PR=1517\frac{30}{PR} = \frac{15}{17} to find PR=34PR = 34. Then, leg QR=34×817=16QR = 34 \times \frac{8}{17} = 16.

Step-by-Step Solution

1
Express the given sine ratio in terms of the triangle sides.
sin(P)=oppositehypotenuse=QRPR=817\sin(P) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{QR}{PR} = \frac{8}{17}
By definition of the sine function in a right triangle.
2
Find the cosine ratio cos(P)\cos(P) using the Pythagorean identity or the 8-15-17 right triangle ratio.
cos(P)=1sin2(P)=164289=1517\cos(P) = \sqrt{1 - \sin^2(P)} = \sqrt{1 - \frac{64}{289}} = \frac{15}{17}
Cosine represents the ratio of the adjacent side (PQPQ) to the hypotenuse (PRPR).
3
Calculate the hypotenuse PRPR using the known leg PQ=30PQ = 30.
PQPR=1517    30PR=1517    PR=34\frac{PQ}{PR} = \frac{15}{17} \implies \frac{30}{PR} = \frac{15}{17} \implies PR = 34
Setting the adjacent side ratio equal to cos(P)\cos(P) solves for the hypotenuse length.
4
Calculate the opposite leg QRQR.
QR=PR×sin(P)=34×817=16QR = PR \times \sin(P) = 34 \times \frac{8}{17} = 16
Multiplying the hypotenuse by sin(P)\sin(P) gives the opposite leg length.

Key Concept

Right Triangle Trigonometry (SOHCAHTOA)
Estimated Time:1m 15s
Rate this question