Question

Difficulty: MediumRight Triangle Trigonometry (SOHCAHTOA)

In right triangle XYZXYZ, the right angle is located at vertex YY. The hypotenuse XZXZ has a length of 3939 inches. If cos(X)=513\cos(X) = \frac{5}{13}, what is the length, in inches, of leg YZYZ?

  1. A
    15
  2. B
    24
  3. 36Answer
  4. D
    42
  5. E
    65

Answer

36 inches
By SOH CAH TOA, cos(X)=adjacenthypotenuse=XY39\cos(X) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{XY}{39}. Setting XY39=513\frac{XY}{39} = \frac{5}{13} gives XY=15XY = 15 inches. Applying the Pythagorean theorem to find the remaining leg YZYZ gives YZ=392152=1296=36YZ = \sqrt{39^2 - 15^2} = \sqrt{1296} = 36 inches. Alternatively, recognizing the ratio cos(X)=513\cos(X) = \frac{5}{13} implies sin(X)=1213\sin(X) = \frac{12}{13} for a 5-12-13 right triangle, so YZ=39×1213=36YZ = 39 \times \frac{12}{13} = 36 inches.

Step-by-Step Solution

1
Use the definition of cosine (SOH CAH TOA) to find the length of leg XYXY, which is adjacent to angle XX.
cos(X)=adjacenthypotenuse=XYXZ    513=XY39    XY=39×513=15\cos(X) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{XY}{XZ} \implies \frac{5}{13} = \frac{XY}{39} \implies XY = 39 \times \frac{5}{13} = 15 inches.
Cosine is defined as the ratio of the adjacent side to the hypotenuse.
2
Apply the Pythagorean theorem (XY2+YZ2=XZ2XY^2 + YZ^2 = XZ^2) to calculate the length of leg YZYZ.
152+YZ2=392    225+YZ2=1521    YZ2=1296    YZ=1296=3615^2 + YZ^2 = 39^2 \implies 225 + YZ^2 = 1521 \implies YZ^2 = 1296 \implies YZ = \sqrt{1296} = 36 inches.
In a right triangle, the sum of the squares of the legs equals the square of the hypotenuse.

Key Concept

Right Triangle Trigonometry (SOHCAHTOA) and Pythagorean Theorem
Estimated Time:1m 0s
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