Question

Difficulty: MediumDirect and Inverse Proportionality

A researcher measured the flow rate, QQ, of various liquids passing through a narrow capillary tube under constant pressure. The viscosity, η\eta, of each liquid and its corresponding flow rate are shown in the table.

LiquidViscosity (η\eta, mPas\text{mPa}\cdot\text{s})Flow rate (QQ, mL/s\text{mL/s})
Liquid 12.02.018.018.0
Liquid 23.03.012.012.0
Liquid 34.04.09.09.0
Liquid 46.06.06.06.0

Based on these results, which of the following equations best represents the relationship between the flow rate, QQ, and the viscosity, η\eta, of the liquids?

  1. A
    Q=36.0ηQ = 36.0\eta
  2. B
    Q=η36.0Q = \frac{\eta}{36.0}
  3. Q=36.0ηQ = \frac{36.0}{\eta}Answer
  4. D
    Q=36.0ηQ = 36.0 - \eta

Answer

Q=36.0ηQ = \frac{36.0}{\eta}
The correct equation is the one stating that flow rate is equal to 36.036.0 divided by viscosity. In an inverse proportionality relationship, the product of the two variables is constant (y×x=ky \times x = k). Multiplying the viscosity by the flow rate for each liquid in the table consistently yields 36.036.0 (e.g., 2.0×18.0=36.02.0 \times 18.0 = 36.0). Solving the equation Q×η=36.0Q \times \eta = 36.0 for QQ results in Q=36.0ηQ = \frac{36.0}{\eta}.

Step-by-Step Solution

1
Analyze the trend in the data table between the viscosity, η\eta, and the flow rate, QQ.
As viscosity increases from 2.02.0 to 6.06.0, the flow rate decreases from 18.018.0 to 6.06.0. This indicates an inverse relationship between the two variables.
Identifying whether the relationship is direct or inverse helps eliminate incorrect equation forms.
2
Determine if the product of the two variables is constant, which is a characteristic of inverse proportionality (yx=ky \cdot x = k).
Calculate the product Q×ηQ \times \eta for each trial:
- For Liquid 1: 2.0×18.0=36.02.0 \times 18.0 = 36.0
- For Liquid 2: 3.0×12.0=36.03.0 \times 12.0 = 36.0
- For Liquid 3: 4.0×9.0=36.04.0 \times 9.0 = 36.0
- For Liquid 4: 6.0×6.0=36.06.0 \times 6.0 = 36.0
The product is constant at 36.036.0.
Finding the constant of proportionality establishes the exact mathematical relationship.
3
Formulate the equation expressing QQ in terms of η\eta.
Since Q×η=36.0Q \times \eta = 36.0, solving for QQ gives Q=36.0ηQ = \frac{36.0}{\eta}.
This matches the target variable representation requested in the prompt.

Key Concept

Inverse Proportionality
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