Question

Difficulty: MediumSystems of Linear and Non-Linear Equations

A system of equations consists of the linear equation y=x+5y = x + 5 and the quadratic equation y=(x3)2+2y = (x - 3)^2 + 2. If the graphs of these two equations intersect at two distinct points, (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2), in the standard (x,y)(x, y) coordinate plane, what is the value of y1+y2y_1 + y_2?

  1. A
    3
  2. B
    7
  3. C
    11
  4. D
    15
  5. 17Answer

Answer

17
To find the points of intersection, we set the two equations equal: x+5=(x3)2+2x + 5 = (x - 3)^2 + 2. Expanding the right side results in x+5=x26x+9+2x + 5 = x^2 - 6x + 9 + 2, which simplifies to x+5=x26x+11x + 5 = x^2 - 6x + 11. Subtracting x+5x + 5 from both sides gives the quadratic equation x27x+6=0x^2 - 7x + 6 = 0. Factoring this equation yields (x1)(x6)=0(x - 1)(x - 6) = 0, giving xx-coordinates of 11 and 66. Substituting these values into the linear equation y=x+5y = x + 5 gives the yy-coordinates: y=1+5=6y = 1 + 5 = 6 and y=6+5=11y = 6 + 5 = 11. The sum of these yy-coordinates is 6+11=176 + 11 = 17.

Step-by-Step Solution

1
Expand the quadratic equation to its standard polynomial form.
y=x26x+11y = x^2 - 6x + 11
Expanding (x3)2+2(x - 3)^2 + 2 allows for easier substitution and algebraic manipulation.
2
Equate the linear and quadratic expressions for yy to find the intersection points.
x+5=x26x+11x + 5 = x^2 - 6x + 11
Setting the two equations equal to each other identifies the xx-coordinates where the graphs intersect.
3
Rearrange the equation into standard quadratic form and solve for xx by factoring.
x27x+6=0    (x1)(x6)=0x^2 - 7x + 6 = 0 \implies (x - 1)(x - 6) = 0, which gives x=1x = 1 and x=6x = 6.
Factoring allows us to find the roots of the quadratic equation representing the intersection xx-coordinates.
4
Substitute the xx-coordinates back into the linear equation y=x+5y = x + 5 to determine the corresponding yy-coordinates.
For x=1x = 1, y=6y = 6. For x=6x = 6, y=11y = 11.
Finding the yy-coordinates corresponding to the intersection points.
5
Calculate the sum of the two yy-coordinates.
6+11=176 + 11 = 17
The question asks specifically for the value of y1+y2y_1 + y_2.

Key Concept

Solving systems of linear and quadratic equations by substitution and factoring
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