Question

Difficulty: MediumSystems of Linear and Non-Linear Equations

The path of a particle in the standard (x,y)(x, y) coordinate plane is described by the linear equation 3xy=23x - y = 2, and the path of another particle is described by the quadratic equation y=x2x7y = x^2 - x - 7. If the two paths intersect at two locations, what is the sum of the yy-coordinates of these intersection points?

Answer: 8

Answer

The sum of the yy-coordinates of the intersection points is 8.
The correct answer is 8. Solving the system by setting x2x7=3x2x^2 - x - 7 = 3x - 2 results in the quadratic equation x24x5=0x^2 - 4x - 5 = 0. Factoring gives (x5)(x+1)=0(x-5)(x+1) = 0, which yields intersection xx-coordinates of x=5x = 5 and x=1x = -1. Substituting these back into the linear equation gives yy-coordinates of 1313 and 5-5. Adding these values together yields 13+(5)=813 + (-5) = 8.

Step-by-Step Solution

1
Express the linear equation in terms of yy.
y=3x2y = 3x - 2
This allows for direct substitution into the quadratic equation.
2
Equate the linear and quadratic expressions to solve for the xx-coordinates of the intersection points.
x2x7=3x2x^2 - x - 7 = 3x - 2
Intersection points share the same coordinates for both equations.
3
Set the quadratic equation to zero.
x24x5=0x^2 - 4x - 5 = 0
This puts the equation in standard form so it can be solved by factoring.
4
Factor the quadratic equation.
(x5)(x+1)=0(x - 5)(x + 1) = 0, so x=5x = 5 or x=1x = -1
Factoring determines the xx-coordinates of the intersection points.
5
Substitute the xx-values into the linear equation to determine the yy-coordinates.
For x=5x = 5, y=13y = 13. For x=1x = -1, y=5y = -5.
Finding the yy-coordinates is necessary to compute their sum.
6
Add the yy-coordinates together.
13+(5)=813 + (-5) = 8
The question asks for the sum of the yy-coordinates of the intersection points.

Key Concept

Solving systems of linear and quadratic equations by substitution and factoring

Alternative Method

We can use Vieta's formulas to find the sum of the yy-coordinates without calculating each individual coordinate. The sum of the yy-coordinates is y1+y2=(3x12)+(3x22)=3(x1+x2)4y_1 + y_2 = (3x_1 - 2) + (3x_2 - 2) = 3(x_1 + x_2) - 4. Since x1x_1 and x2x_2 are the roots of x24x5=0x^2 - 4x - 5 = 0, Vieta's formulas state that the sum of the roots is x1+x2=41=4x_1 + x_2 = -\frac{-4}{1} = 4. Substituting this value into our sum expression yields 3(4)4=124=83(4) - 4 = 12 - 4 = 8.
Estimated Time:1m 30s
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