Question

Difficulty: EasyProperties of Quadrilaterals

In isosceles trapezoid ABCDABCD, the parallel bases are ABAB and CDCD. If the measure of interior angle AA is 7070^\circ, what is the measure, in degrees, of interior angle CC?

Answer: 110 degrees

Answer

The measure of interior angle CC is 110110 degrees.
Since the trapezoid is isosceles with bases ABAB and CDCD, the base angles A\angle A and B\angle B are congruent, so B=70\angle B = 70^\circ. The consecutive interior angles along the leg BCBC are supplementary because ABCDAB \parallel CD, which means B+C=180\angle B + \angle C = 180^\circ. Solving for C\angle C gives 18070=110180^\circ - 70^\circ = 110^\circ.

Step-by-Step Solution

1
Find the measure of angle BB using the properties of an isosceles trapezoid.
B=70\angle B = 70^\circ
In an isosceles trapezoid, the angles sharing a base are congruent. Since ABAB is a base, A=B=70\angle A = \angle B = 70^\circ.
2
Calculate the measure of angle CC using the parallel lines property.
C=110\angle C = 110^\circ
Because the bases ABAB and CDCD are parallel, the consecutive interior angles B\angle B and C\angle C must sum to 180180^\circ. Therefore, C=18070=110\angle C = 180^\circ - 70^\circ = 110^\circ.

Key Concept

Properties of an isosceles trapezoid

Alternative Method

Since the sum of interior angles in any quadrilateral is 360360^\circ, and in an isosceles trapezoid the base angles are equal (A=B=70\angle A = \angle B = 70^\circ and C=D\angle C = \angle D), we can write 70+70+C+D=36070^\circ + 70^\circ + \angle C + \angle D = 360^\circ. Since C=D\angle C = \angle D, this simplifies to 140+2C=360    2C=220    C=110140^\circ + 2\angle C = 360^\circ \implies 2\angle C = 220^\circ \implies \angle C = 110^\circ.
Estimated Time:45s
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