Question

Difficulty: EasySimplifying Expressions and Combining Like Terms

For all real numbers xx and yy, which of the following is equivalent to the expression (x2y)2(x25xy)(x - 2y)^2 - (x^2 - 5xy)?

  1. A
    4y+xy4y + xy
  2. B
    4y29xy4y^2 - 9xy
  3. C
    4y2+5xy4y^2 + 5xy
  4. 4y2+xy4y^2 + xyAnswer
  5. E
    4y25xy4y^2 - 5xy

Answer

The expression is equivalent to 4y2+xy4y^2 + xy.
Expanding (x2y)2(x - 2y)^2 yields x24xy+4y2x^2 - 4xy + 4y^2. Distributing the negative sign to (x25xy)-(x^2 - 5xy) gives x2+5xy-x^2 + 5xy. Combining the results yields (x2x2)+(4xy+5xy)+4y2=xy+4y2(x^2 - x^2) + (-4xy + 5xy) + 4y^2 = xy + 4y^2, which is equivalent to 4y2+xy4y^2 + xy.

Step-by-Step Solution

1
Expand the squared binomial (x2y)2(x - 2y)^2.
x24xy+4y2x^2 - 4xy + 4y^2
Apply the binomial squaring formula (ab)2=a22ab+b2(a - b)^2 = a^2 - 2ab + b^2 to expand the expression.
2
Distribute the negative sign across the second parenthetical expression (x25xy)-(x^2 - 5xy).
x2+5xy-x^2 + 5xy
Distributing the negative sign changes the signs of both terms inside the parentheses.
3
Combine like terms from the expanded parts.
xy+4y2xy + 4y^2
Group and add coefficients of the like terms: (x2x2)+(4xy+5xy)+4y2=0+xy+4y2(x^2 - x^2) + (-4xy + 5xy) + 4y^2 = 0 + xy + 4y^2.

Key Concept

Simplifying Expressions and Combining Like Terms
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