Question

Difficulty: MediumConic Sections

A circle in the standard (x,y)(x, y) coordinate plane is defined by the equation x2+y24x+6y12=0x^2 + y^2 - 4x + 6y - 12 = 0. What is the radius of this circle?

  1. A
    2525
  2. B
    232\sqrt{3}
  3. 55Answer
  4. D
    88
  5. E
    17\sqrt{17}

Answer

The radius of the circle is 5.
The correct answer is 5. Grouping the xx-terms and yy-terms of the equation x2+y24x+6y12=0x^2 + y^2 - 4x + 6y - 12 = 0 gives (x24x)+(y2+6y)=12(x^2 - 4x) + (y^2 + 6y) = 12. Completing the square requires adding (42)2=4(\frac{-4}{2})^2 = 4 and (62)2=9(\frac{6}{2})^2 = 9 to both sides, yielding (x24x+4)+(y2+6y+9)=12+4+9(x^2 - 4x + 4) + (y^2 + 6y + 9) = 12 + 4 + 9, which simplifies to (x2)2+(y+3)2=25(x-2)^2 + (y+3)^2 = 25. In the standard circle equation form (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2, r2=25r^2 = 25, meaning the radius rr is 25=5\sqrt{25} = 5.

Step-by-Step Solution

1
Group the xx-terms and yy-terms, and move the constant term to the right side of the equation.
(x24x)+(y2+6y)=12(x^2 - 4x) + (y^2 + 6y) = 12
This prepares the quadratic expression to be written in standard circle form by completing the square.
2
Find the constant values needed to complete the square for both the xx and yy variables. Add these constants to both sides of the equation.
(x24x+4)+(y2+6y+9)=12+4+9(x^2 - 4x + 4) + (y^2 + 6y + 9) = 12 + 4 + 9
The constant for xx is (42)2=4(\frac{-4}{2})^2 = 4, and the constant for yy is (62)2=9(\frac{6}{2})^2 = 9. Adding them to both sides maintains equality.
3
Factor the perfect square trinomials on the left side and simplify the right side.
(x2)2+(y+3)2=25(x-2)^2 + (y+3)^2 = 25
This puts the equation in the standard form (xh)2+(yk)2=r2(x-h)^2 + (y-k)^2 = r^2.
4
Identify r2r^2 from the standard form and solve for the radius rr.
r=25=5r = \sqrt{25} = 5
Taking the square root of the constant on the right side yields the radius of the circle.

Key Concept

Rewriting a circle's equation from general form to standard form by completing the square to find its radius.

Alternative Method

For a circle given in the general form x2+y2+Dx+Ey+F=0x^2 + y^2 + Dx + Ey + F = 0, the radius can be calculated directly using the formula r=12D2+E24Fr = \frac{1}{2}\sqrt{D^2 + E^2 - 4F}. Substituting the coefficients D=4D = -4, E=6E = 6, and F=12F = -12 gives: r=12(4)2+624(12)=1216+36+48=12100=12(10)=5r = \frac{1}{2}\sqrt{(-4)^2 + 6^2 - 4(-12)} = \frac{1}{2}\sqrt{16 + 36 + 48} = \frac{1}{2}\sqrt{100} = \frac{1}{2}(10) = 5.
Estimated Time:1m 30s
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