Question

Difficulty: MediumSolving Quadratic Equations by Factoring

For a certain positive number yy, the product of yy and the quantity 2y+52y + 5 is equal to 1212. What is the value of yy?

Answer: 1.5

Answer

The positive value of yy is 1.51.5.
The correct answer is 1.51.5. By translating the word problem, we obtain y(2y+5)=12y(2y + 5) = 12. Expanding this gives 2y2+5y=122y^2 + 5y = 12, and subtracting 1212 from both sides yields the standard quadratic equation 2y2+5y12=02y^2 + 5y - 12 = 0. Factoring this expression gives (2y3)(y+4)=0(2y - 3)(y + 4) = 0. Setting the first factor to zero yields y=1.5y = 1.5, which is positive and therefore satisfies the given condition.

Step-by-Step Solution

1
Write the equation representing the relationship.
y(2y+5)=12y(2y + 5) = 12
To translate the verbal description into an algebraic equation.
2
Distribute yy and set the equation equal to zero.
2y2+5y12=02y^2 + 5y - 12 = 0
To put the quadratic equation into standard form ay2+by+c=0ay^2 + by + c = 0 so it can be factored.
3
Factor the quadratic equation.
(2y3)(y+4)=0(2y - 3)(y + 4) = 0
To find the factors that multiply to give the quadratic expression.
4
Solve for yy and apply the constraint.
y=1.5y = 1.5
Setting the factors to zero gives y=1.5y = 1.5 and y=4y = -4. Since the problem states yy is positive, we select the positive root.

Key Concept

Solving a non-monic quadratic equation by factoring after translating a verbal description into algebra.
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