Question

Difficulty: MediumComplex Numbers and Operations

For the imaginary unit ii, where i2=1i^2 = -1, which of the following complex numbers is equal to 8+i3+2i\frac{8 + i}{3 + 2i}?

  1. A
    2213i\frac{22}{13} - i
  2. B
    265135i\frac{26}{5} - \frac{13}{5}i
  3. C
    2 + i
  4. 2 - iAnswer
  5. E
    83+12i\frac{8}{3} + \frac{1}{2}i

Answer

The complex number 2i2 - i
To divide two complex numbers, we multiply both the numerator and denominator by the complex conjugate of the denominator, which is 32i3 - 2i. Expanding the numerator gives (8+i)(32i)=2416i+3i2i2=2613i(8 + i)(3 - 2i) = 24 - 16i + 3i - 2i^2 = 26 - 13i because i2=1i^2 = -1. Expanding the denominator yields (3+2i)(32i)=94i2=9+4=13(3 + 2i)(3 - 2i) = 9 - 4i^2 = 9 + 4 = 13. Dividing the terms of the numerator by the denominator gives 2613i13=2i\frac{26 - 13i}{13} = 2 - i.

Step-by-Step Solution

1
Multiply the numerator and the denominator of the fraction by the complex conjugate of the denominator.
8+i3+2i32i32i=(8+i)(32i)(3+2i)(32i)\frac{8 + i}{3 + 2i} \cdot \frac{3 - 2i}{3 - 2i} = \frac{(8 + i)(3 - 2i)}{(3 + 2i)(3 - 2i)}
Multiplying by the conjugate rationalizes the denominator, converting it into a real number.
2
Expand the numerator and the denominator using binomial multiplication.
Numerator: (8+i)(32i)=2416i+3i2i2(8 + i)(3 - 2i) = 24 - 16i + 3i - 2i^2
Denominator: (3+2i)(32i)=96i+6i4i2=94i2(3 + 2i)(3 - 2i) = 9 - 6i + 6i - 4i^2 = 9 - 4i^2
Distribute each term in the first binomial to each term in the second binomial.
3
Substitute i2=1i^2 = -1 and simplify both expressions.
Numerator: 2413i2(1)=2413i+2=2613i24 - 13i - 2(-1) = 24 - 13i + 2 = 26 - 13i
Denominator: 94(1)=9+4=139 - 4(-1) = 9 + 4 = 13
The definition of the imaginary unit is i2=1i^2 = -1.
4
Divide each term of the simplified numerator by the simplified denominator.
2613i13=261313i13=2i\frac{26 - 13i}{13} = \frac{26}{13} - \frac{13i}{13} = 2 - i
Separate the real and imaginary parts to write the complex number in standard form a+bia + bi.

Key Concept

Division of complex numbers using the complex conjugate of the denominator.

Alternative Method

Instead of dividing directly, let the result be x+yix + yi. Then (x+yi)(3+2i)=8+i(x + yi)(3 + 2i) = 8 + i. Expanding this gives (3x2y)+(2x+3y)i=8+i(3x - 2y) + (2x + 3y)i = 8 + i. Equating the real and imaginary parts gives the system of equations 3x2y=83x - 2y = 8 and 2x+3y=12x + 3y = 1. Solving this system yields x=2x = 2 and y=1y = -1, which corresponds to the complex number 2i2 - i.
Estimated Time:1m 30s
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