Question

Difficulty: EasyProperties of Exponents in Algebraic Expressions

For x0x \neq 0, the expression (x2)5xk\frac{(x^2)^5}{x^k} simplifies to x6x^6. What is the value of the exponent kk?

Answer: 4

Answer

The value of the exponent kk is 4.
Applying the power of a power rule to the numerator yields (x2)5=x10(x^2)^5 = x^{10}. Next, applying the quotient rule to divide x10x^{10} by xkx^k yields x10kx^{10-k}. Setting this equal to the simplified term x6x^6 leads to the exponent equation 10k=610 - k = 6. Solving this equation gives the final result k=4k = 4.

Step-by-Step Solution

1
Simplify the numerator expression (x2)5(x^2)^5
x10x^{10}
Multiply the exponents when raising a power to another power: (xa)b=xab(x^a)^b = x^{ab}.
2
Simplify the division of the two exponential expressions x10xk\frac{x^{10}}{x^k}
x10kx^{10-k}
Subtract the exponent of the denominator from the exponent of the numerator: xaxb=xab\frac{x^a}{x^b} = x^{a-b}.
3
Solve the linear equation for kk using the target exponent 6
k=4k = 4
Equating the exponent 10k10-k to 66 gives 10k=610-k=6. Subtracting 10 from both sides gives k=4-k = -4, so k=4k = 4.

Key Concept

Applying properties of exponents in algebraic expressions, specifically the power of a power rule and the quotient rule.
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