Question

Difficulty: EasyMatrices and Matrix Operations

Let matrix A=(2513)A = \begin{pmatrix} 2 & 5 \\ -1 & 3 \end{pmatrix} and matrix B=(4231)B = \begin{pmatrix} 4 & -2 \\ 3 & 1 \end{pmatrix}. If matrix C=2A+3BC = 2A + 3B, what is the value of the entry in the second row and first column of matrix CC?

Answer: 7

Answer

The entry in the second row and first column of matrix CC is 7.
The entry in the second row, first column of matrix CC, denoted as c2,1c_{2,1}, is calculated by multiplying the corresponding entry in matrix AA (a2,1=1a_{2,1} = -1) by 2 and the corresponding entry in matrix BB (b2,1=3b_{2,1} = 3) by 3, and then adding the results: 2(1)+3(3)=2+9=72(-1) + 3(3) = -2 + 9 = 7.

Step-by-Step Solution

1
Locate the element in the second row, first column of both matrices AA and BB.
The element in the second row, first column of AA (designated a2,1a_{2,1}) is 1-1, and the element in the second row, first column of BB (designated b2,1b_{2,1}) is 33.
To find a specific entry in the resulting matrix C=2A+3BC = 2A + 3B, we perform the scalar multiplication and addition operations on the corresponding entries in the same position of matrices AA and BB.
2
Multiply the corresponding elements by their respective scalar factors.
For matrix AA, 2×(1)=22 \times (-1) = -2. For matrix BB, 3×3=93 \times 3 = 9.
Scalar multiplication requires multiplying each individual entry of a matrix by the given scalar factor.
3
Add the two resulting values to find the entry for matrix CC.
-2 + 9 = 7
Matrix addition is performed by adding the corresponding elements of the matrices.

Key Concept

Matrix scalar multiplication and addition of corresponding elements
Estimated Time:45s
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