Question

Difficulty: Very hardSolving Linear Equations

An online retailer determines that the cost to ship a package of weight ww pounds is given by the linear expression C(w)=kw+bC(w) = kw + b, where kk and bb are constants. Shipping a 33-pound package costs 11.5011.50 dollars, and shipping an 88-pound package costs 24.0024.00 dollars. If the total shipping cost for two packages is 47.0047.00 dollars, and one of the packages weighs 55 pounds, what is the weight, in pounds, of the other package?

Answer: 10.6 pounds

Answer

The weight of the other package is 10.6 pounds.
The correct weight of 10.6 pounds is found by setting up a linear cost function C(w)=2.5w+4C(w) = 2.5w + 4 using the two data points, calculating the cost of the 5-pound package as 16.5016.50 dollars, subtracting this from the total cost of 47.0047.00 dollars to get 30.5030.50 dollars, and solving 2.5w+4=30.502.5w + 4 = 30.50 for the weight.

Step-by-Step Solution

1
Set up the linear system from the given costs
3k+b=11.503k + b = 11.50 and 8k+b=24.008k + b = 24.00
To determine the relationship between weight and shipping cost.
2
Solve for the slope kk
k=2.50k = 2.50
Subtracting the first equation from the second eliminates bb.
3
Solve for the intercept bb
b=4.00b = 4.00
Substitute k=2.50k = 2.50 back into the first equation.
4
Determine the cost of the 5-pound package
C(5)=16.50C(5) = 16.50 dollars
Evaluate the linear expression 2.50(5)+4.002.50(5) + 4.00.
5
Determine the remaining cost for the second package
C(w2)=30.50C(w_2) = 30.50 dollars
Subtract the cost of the first package from the total cost (47.0016.5047.00 - 16.50).
6
Solve the linear equation for the second package's weight
w2=10.6w_2 = 10.6
Solve 2.50w2+4.00=30.502.50w_2 + 4.00 = 30.50 for w2w_2.

Key Concept

Solving Linear Equations
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