Question

Difficulty: MediumParallel and Perpendicular Lines

In the standard (x,y)(x, y) coordinate plane, line L1L_1 passes through the points (1,3)(1, 3) and (4,8)(4, 8). Line L2L_2 is perpendicular to line L1L_1. If line L2L_2 passes through the points (5,k)(5, k) and (10,1)(10, 1), what is the value of kk?

Answer: 4

Answer

The value of kk is 44.
The correct answer is 44. First, determine the slope of line L1L_1 using the points (1,3)(1, 3) and (4,8)(4, 8), which is 8341=53\frac{8 - 3}{4 - 1} = \frac{5}{3}. Because line L2L_2 is perpendicular to L1L_1, its slope must be the negative reciprocal of 53\frac{5}{3}, which is 35-\frac{3}{5}. Next, set up the slope equation for L2L_2 with the points (5,k)(5, k) and (10,1)(10, 1), yielding 1k105=35\frac{1 - k}{10 - 5} = -\frac{3}{5}. Simplifying the equation gives 1k5=35\frac{1 - k}{5} = -\frac{3}{5}, which reduces to 1k=31 - k = -3. Solving for kk gives k=4k = 4.

Step-by-Step Solution

1
Calculate the slope of line L1L_1 using the coordinates of the two given points, (1,3)(1, 3) and (4,8)(4, 8).
The slope of line L1L_1 is 53\frac{5}{3}.
Using the slope formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1}, we find m1=8341=53m_1 = \frac{8 - 3}{4 - 1} = \frac{5}{3}.
2
Determine the slope of line L2L_2 based on the perpendicular relationship between L1L_1 and L2L_2.
The slope of line L2L_2 is 35-\frac{3}{5}.
Perpendicular lines have slopes that are negative reciprocals of each other. The negative reciprocal of 53\frac{5}{3} is 35-\frac{3}{5}.
3
Use the coordinates (5,k)(5, k) and (10,1)(10, 1) on line L2L_2 to write an expression for its slope, set it equal to 35-\frac{3}{5}, and solve for kk.
k=4k = 4
The slope expression is 1k105=1k5\frac{1 - k}{10 - 5} = \frac{1 - k}{5}. Setting this equal to the perpendicular slope gives 1k5=35\frac{1 - k}{5} = -\frac{3}{5}. Multiplying both sides by 55 results in 1k=31 - k = -3. Adding kk to both sides and adding 33 to both sides yields k=4k = 4.

Key Concept

The slopes of perpendicular lines in a coordinate plane are negative reciprocals of each other, meaning their product is 1-1 (m1m2=1m_1 \cdot m_2 = -1).
Estimated Time:1m 15s
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