Question

Difficulty: HardTranslating and Solving Algebraic Word Problems

A chemist wants to create 100100 milliliters of a 42.5%42.5\% acid solution by mixing three different acid solutions: a 10%10\% acid solution, a 20%20\% acid solution, and an 80%80\% acid solution. She decides that the volume of the 20%20\% acid solution used must be exactly 33 times the volume of the 10%10\% acid solution used. What is the difference, in milliliters, between the volume of the 80%80\% acid solution and the volume of the 10%10\% acid solution used in the final mixture?

Answer: 25 milliliters

Answer

The difference between the volume of the 80%80\% acid solution and the volume of the 10%10\% acid solution is 2525 milliliters.
Solving the system of equations yields that 1515 milliliters of the 10%10\% solution, 4545 milliliters of the 20%20\% solution, and 4040 milliliters of the 80%80\% solution are needed. The difference between the volume of the 80%80\% solution and the 10%10\% solution is 4015=2540 - 15 = 25 milliliters.

Step-by-Step Solution

1
Define variables for the volume of each acid solution.
Let xx be the volume of the 10%10\% solution, yy be the volume of the 20%20\% solution, and zz be the volume of the 80%80\% solution.
This establishes algebraic representations for the unknowns.
2
Set up a system of linear equations based on the relationships given in the problem statement.
x+y+z=100x + y + z = 100 (total volume)
y=3xy = 3x (relationship between the 20%20\% and 10%10\% solutions)
0.10x+0.20y+0.80z=42.50.10x + 0.20y + 0.80z = 42.5 (total acid content)
Translating word problems to mathematical equations allows us to solve for the variables systematically.
3
Reduce the system to a single equation in terms of xx by substituting y=3xy = 3x and expressing zz in terms of xx.
4x+z=100    z=1004x4x + z = 100 \implies z = 100 - 4x
Substitute both into the acid equation:
0.10x+0.20(3x)+0.80(1004x)=42.50.10x + 0.20(3x) + 0.80(100 - 4x) = 42.5
Substitution simplifies the system of equations to a single linear equation with one variable.
4
Solve the simplified linear equation for xx.
0.70x+803.20x=42.5    2.50x=37.5    x=150.70x + 80 - 3.20x = 42.5 \implies -2.50x = -37.5 \implies x = 15
This determines the volume of the 10%10\% acid solution.
5
Calculate the volume of the 80%80\% solution, zz.
z=1004(15)=40z = 100 - 4(15) = 40
This determines the volume of the 80%80\% acid solution.
6
Find the difference between zz and xx.
zx=4015=25z - x = 40 - 15 = 25
The question asks for the difference between these two volumes.

Key Concept

Translating and solving systems of linear equations from verbal descriptions (mixture problems).
Estimated Time:2m 30s
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