Question

Difficulty: MediumConic Sections

In the standard (x,y)(x, y) coordinate plane, an ellipse is centered at the origin (0,0)(0, 0) and has vertices at (5,0)(-5, 0) and (5,0)(5, 0). If the distance between the two foci of the ellipse is 88, what is the length of the minor axis of the ellipse?

Answer: 6 coordinate units

Answer

The correct answer is 6.
The correct answer is 6 because the ellipse has a horizontal major axis with a=5a = 5 and focal distance c=4c = 4. Using the relationship c2=a2b2c^2 = a^2 - b^2, we solve for the semi-minor axis bb to get b=3b = 3. The total length of the minor axis is 2b=62b = 6.

Step-by-Step Solution

1
Determine the semi-major axis length aa.
a=5a = 5
The vertices are at (±5,0)(\pm 5, 0), which are 55 units from the center (0,0)(0, 0) along the major axis.
2
Determine the distance from the center to each focus cc.
c=4c = 4
The distance between the two foci is 2c=82c = 8, so the distance from the center to a focus is c=4c = 4.
3
Find the semi-minor axis length bb.
b=3b = 3
Using the relation c2=a2b2c^2 = a^2 - b^2 for ellipses, we get 42=52b2    b2=9    b=34^2 = 5^2 - b^2 \implies b^2 = 9 \implies b = 3.
4
Calculate the full length of the minor axis.
66
The length of the minor axis is 2b=2(3)=62b = 2(3) = 6.

Key Concept

The relationship between the semi-major axis, semi-minor axis, and focal distance of an ellipse.
Estimated Time:1m 30s
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