Question

Difficulty: MediumLaw of Sines and Law of Cosines

In ABC\triangle ABC, the length of side aa (opposite angle AA) is 99 inches, the length of side bb (opposite angle BB) is 1212 inches, and the measure of angle BB is 4545^\circ. What is the exact value of sinA\sin A?

  1. 328\frac{3\sqrt{2}}{8}Answer
  2. B
    223\frac{2\sqrt{2}}{3}
  3. C
    324\frac{3\sqrt{2}}{4}
  4. D
    38\frac{3}{8}
  5. E
    423\frac{4\sqrt{2}}{3}

Answer

The exact value of sinA\sin A is 328\frac{3\sqrt{2}}{8}.
According to the Law of Sines, sinAa=sinBb\frac{\sin A}{a} = \frac{\sin B}{b}. Substituting a=9a = 9, b=12b = 12, and B=45B = 45^\circ yields sinA9=sin4512\frac{\sin A}{9} = \frac{\sin 45^\circ}{12}. Multiplying both sides by 99 and substituting sin45=22\sin 45^\circ = \frac{\sqrt{2}}{2} gives sinA=92212=9224=328\sin A = \frac{9 \cdot \frac{\sqrt{2}}{2}}{12} = \frac{9\sqrt{2}}{24} = \frac{3\sqrt{2}}{8}.

Step-by-Step Solution

1
State the Law of Sines for the given triangle components.
sinAa=sinBb\frac{\sin A}{a} = \frac{\sin B}{b}
The Law of Sines relates the sines of angles to their opposite side lengths in any triangle.
2
Substitute the known values (a=9a = 9, b=12b = 12, and B=45B = 45^\circ) into the formula.
sinA9=sin4512\frac{\sin A}{9} = \frac{\sin 45^\circ}{12}
Plugging in the given numbers isolates the unknown quantity sinA\sin A.
3
Solve for sinA\sin A and substitute the exact value of sin45=22\sin 45^\circ = \frac{\sqrt{2}}{2}.
sinA=9sin4512=92212=9224=328\sin A = \frac{9 \cdot \sin 45^\circ}{12} = \frac{9 \cdot \frac{\sqrt{2}}{2}}{12} = \frac{9\sqrt{2}}{24} = \frac{3\sqrt{2}}{8}
Simplifying the fraction gives the exact trigonometric ratio.

Key Concept

Law of Sines
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