Question

Difficulty: HardMaking Predictions Based on Models

A team of astrophysicists modeled the equilibrium surface temperature, TT (in Kelvin, K\text{K}), of airless rocky planets orbiting a distant star. According to the model, the temperature is predicted by the following equation:

T=T0(1a)1/4D1/2T = T_0 (1 - a)^{1/4} D^{-1/2}

where:
- T0T_0 is a star-specific constant equal to 400 K400\text{ K}.
- aa is the planet's albedo (reflectivity), ranging from 0.00.0 to 1.01.0.
- DD is the planet's distance from the star in astronomical units (AU\text{AU}).

Based on this model, arrange the four planets (W, X, Y, and Z) shown in the diagram in order of their predicted equilibrium surface temperature, from lowest to highest.

  1. 1Planet W (a=0.9375a = 0.9375, D=4.0 AUD = 4.0\text{ AU})
  2. 2Planet X (a=0.9375a = 0.9375, D=1.0 AUD = 1.0\text{ AU})
  3. 3Planet Y (a=0.0a = 0.0, D=1.0 AUD = 1.0\text{ AU})
  4. 4Planet Z (a=0.0a = 0.0, D=0.25 AUD = 0.25\text{ AU})

Answer

The correct order of the planets from lowest to highest predicted equilibrium surface temperature is Planet W, Planet X, Planet Y, and Planet Z.
Substituting the specific physical parameters into the model equation T=400(1a)1/4D1/2T = 400(1-a)^{1/4}D^{-1/2} yields the exact temperatures: 100 K100\text{ K} for Planet W, 200 K200\text{ K} for Planet X, 400 K400\text{ K} for Planet Y, and 800 K800\text{ K} for Planet Z, demonstrating an ascending sequence from W to Z.

Step-by-Step Solution

1
Identify the parameters of each planet and analyze the model equation: T=T0(1a)1/4D1/2T = T_0 (1 - a)^{1/4} D^{-1/2}.
The constant T0=400 KT_0 = 400\text{ K}. Planet W has a=0.9375,D=4.0 AUa = 0.9375, D = 4.0\text{ AU}. Planet X has a=0.9375,D=1.0 AUa = 0.9375, D = 1.0\text{ AU}. Planet Y has a=0.0,D=1.0 AUa = 0.0, D = 1.0\text{ AU}. Planet Z has a=0.0,D=0.25 AUa = 0.0, D = 0.25\text{ AU}.
Listing the parameters clearly helps set up the mathematical calculations for comparison.
2
Calculate the predicted equilibrium temperature for Planet W and Planet X.
For Planet W, T=400(10.9375)1/4(4.0)1/2=400(0.0625)1/4(0.5)=400(0.5)(0.5)=100 KT = 400(1 - 0.9375)^{1/4}(4.0)^{-1/2} = 400(0.0625)^{1/4}(0.5) = 400(0.5)(0.5) = 100\text{ K}. For Planet X, T=400(10.9375)1/4(1.0)1/2=400(0.0625)1/4(1.0)=400(0.5)(1.0)=200 KT = 400(1 - 0.9375)^{1/4}(1.0)^{-1/2} = 400(0.0625)^{1/4}(1.0) = 400(0.5)(1.0) = 200\text{ K}.
Evaluating the fractional power (1/16)1/4=1/2(1/16)^{1/4} = 1/2 and distance roots allows us to determine the temperatures for high-albedo planets.
3
Calculate the predicted equilibrium temperature for Planet Y and Planet Z.
For Planet Y, T=400(10.0)1/4(1.0)1/2=400(1.0)(1.0)=400 KT = 400(1 - 0.0)^{1/4}(1.0)^{-1/2} = 400(1.0)(1.0) = 400\text{ K}. For Planet Z, T=400(10.0)1/4(0.25)1/2=400(1.0)(2.0)=800 KT = 400(1 - 0.0)^{1/4}(0.25)^{-1/2} = 400(1.0)(2.0) = 800\text{ K}.
Evaluating the model for the zero-albedo planets establishes their temperatures.
4
Compare the calculated temperatures to order the planets from lowest to highest.
Planet W (100 K100\text{ K}) < Planet X (200 K200\text{ K}) < Planet Y (400 K400\text{ K}) < Planet Z (800 K800\text{ K}). The order is Planet W, Planet X, Planet Y, Planet Z.
Arranging the numerical values in ascending order directly determines the correct sequence.

Key Concept

Applying mathematical models with fractional and negative exponents to predict and compare astronomical states.
Estimated Time:2m 0s
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