Question

Difficulty: MediumIntegers, Absolute Value, and Number Lines

On a standard number line, point AA has coordinate 15-15 and point BB has coordinate 1717. Point CC is located to the right of point BB such that the distance between AA and CC is exactly 33 times the distance between BB and CC. What is the coordinate of point CC?

Answer: 33

Answer

The coordinate of point CC is 33.
The correct coordinate is found by setting up the distance equation for point CC (with coordinate c>17c > 17) relative to A(15)A(-15) and B(17)B(17). The distance ACAC is c(15)=c+15c - (-15) = c + 15, and the distance BCBC is c17c - 17. Setting c+15=3(c17)c + 15 = 3(c - 17) and solving yields c=33c = 33, which is to the right of BB.

Step-by-Step Solution

1
Define the variable for the coordinate of point C and write the expressions for distances.
Let cc be the coordinate of point CC. The distance between AA and CC is c(15)=c+15|c - (-15)| = |c + 15|, and the distance between BB and CC is c17|c - 17|. Since point CC is to the right of point BB (which is at 1717), we know c>17c > 17, so c+15=c+15|c + 15| = c + 15 and c17=c17|c - 17| = c - 17.
To set up an algebraic equation representing the physical distance relations on the number line.
2
Set up the equation using the given relationship.
The equation is c+15=3(c17)c + 15 = 3(c - 17).
The problem states the distance between AA and CC is 33 times the distance between BB and CC.
3
Solve the equation for cc.
c+15=3c51    15+51=3cc    66=2c    c=33c + 15 = 3c - 51 \implies 15 + 51 = 3c - c \implies 66 = 2c \implies c = 33.
To find the coordinate of point CC.

Key Concept

Calculating distances between points on a number line using absolute value and solving the resulting equations.

Alternative Method

Use geometric visualization: The distance from A(15)A(-15) to B(17)B(17) is 17(15)=3217 - (-15) = 32 units. Since point CC lies to the right of BB, the distance ACAC is the sum of ABAB and BCBC. Therefore, AC=32+BCAC = 32 + BC. We are given that AC=3×BCAC = 3 \times BC. Substituting this gives 32+BC=3×BC    2×BC=32    BC=1632 + BC = 3 \times BC \implies 2 \times BC = 32 \implies BC = 16. Since CC is 16 units to the right of B(17)B(17), its coordinate is 17+16=3317 + 16 = 33.
Estimated Time:1m 30s
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