Question

Difficulty: Very hardTriangle Properties and Angle Theorems

A non-degenerate triangle has side lengths of 55, 1212, and xx. A second non-degenerate triangle has side lengths of xx, 1010, and yy. If xx and yy must be integers, and the perimeter of the second triangle is the minimum possible integer value, what is the sum of all possible values of yy?

  1. A
    1
  2. B
    3
  3. 6Answer
  4. D
    10
  5. E
    27

Answer

6
The correct answer is 6. By applying the Triangle Inequality Theorem, the shared side length xx of the first triangle must satisfy 125<x<12+512 - 5 < x < 12 + 5, which simplifies to 7<x<177 < x < 17. Since xx must be an integer, its possible values are {8,9,10,11,12,13,14,15,16}\{8, 9, 10, 11, 12, 13, 14, 15, 16\}. For the second triangle with side lengths xx, 1010, and yy, the Triangle Inequality Theorem requires x10<y<x+10|x - 10| < y < x + 10. To minimize the perimeter P=x+10+yP = x + 10 + y, we minimize x+yx + y. Checking the possible values of xx, we find that when x=8x = 8, the minimum integer value for yy is 33 (giving P=21P = 21); when x=9x = 9, the minimum integer value for yy is 22 (giving P=21P = 21); and when x=10x = 10, the minimum integer value for yy is 11 (giving P=21P = 21). For any x11x \ge 11, the minimum value of yy is x9x - 9, resulting in a perimeter of at least 2323. Therefore, the minimum perimeter of the second triangle is 2121, which is achieved when yy is 33, 22, or 11. The sum of these values of yy is 1+2+3=61 + 2 + 3 = 6.

Step-by-Step Solution

1
Apply the Triangle Inequality Theorem to the first triangle to find the range of the shared side length xx.
7<x<177 < x < 17
The sum of any two side lengths of a triangle must be strictly greater than the third side length. Thus, 125<x<12+512 - 5 < x < 12 + 5.
2
List the possible integer values of xx based on the range.
x{8,9,10,11,12,13,14,15,16}x \in \{8, 9, 10, 11, 12, 13, 14, 15, 16\}
The problem states that xx must be an integer.
3
Apply the Triangle Inequality Theorem to the second triangle with sides xx, 1010, and yy to express the range of yy in terms of xx.
x10<y<x+10|x - 10| < y < x + 10
The third side length yy must be strictly between the difference and the sum of the other two sides (xx and 1010).
4
Determine the minimum integer value of the perimeter of the second triangle, P=x+10+yP = x + 10 + y, by testing the possible values of xx and finding the minimum integer yy for each.
The minimum perimeter is 2121, achieved when (x,y)=(8,3)(x, y) = (8, 3), (9,2)(9, 2), or (10,1)(10, 1).
Minimizing the perimeter P=x+y+10P = x + y + 10 is equivalent to minimizing the sum x+yx + y for integer values of y>x10y > |x - 10|.
5
Sum the possible integer values of yy that yield the minimum perimeter.
3+2+1=63 + 2 + 1 = 6
We need to find the sum of all possible values of yy that result in the minimum perimeter of 2121.

Key Concept

Triangle Inequality Theorem and Perimeter Optimization
Estimated Time:3m 0s
Rate this question