Question

Difficulty: MediumScientific Notation and Unit Conversions

In a biochemistry laboratory experiment, a microfluidic device is calibrated to pump an enzyme solution into a reaction chamber at a constant rate of 4.8×1054.8 \times 10^{-5} liters per minute (L/min\text{L/min}). What is this pump rate in microliters per second (μL/s\mu\text{L/s})?

Answer: 0.8 μL/s

Answer

The correct pump rate is 0.8 microliters per second.
To convert 4.8×105 L/min4.8 \times 10^{-5}\text{ L/min} to μL/s\mu\text{L/s}, first convert liters to microliters by multiplying by 106 μL/L10^6\ \mu\text{L/L}, which gives 48 μL/min48\ \mu\text{L/min}. Next, convert minutes to seconds by dividing by 60 s/min60\text{ s/min} to get 0.8 μL/s0.8\ \mu\text{L/s}.

Step-by-Step Solution

1
Convert the volume flow rate from liters per minute to microliters per minute.
48μL/min48 \mu\text{L/min}
Since 1 L=106 μL1\text{ L} = 10^6\ \mu\text{L}, multiplying 4.8×105 L/min4.8 \times 10^{-5}\text{ L/min} by 106 μL/L10^6\ \mu\text{L/L} yields 48 μL/min48\ \mu\text{L/min}.
2
Convert the flow rate from microliters per minute to microliters per second.
0.8μL/s0.8 \mu\text{L/s}
Since 1 minute=60 seconds1\text{ minute} = 60\text{ seconds}, dividing 48 μL/min48\ \mu\text{L/min} by 60 s/min60\text{ s/min} yields 0.8 μL/s0.8\ \mu\text{L/s}.

Key Concept

Scientific Notation and Unit Conversions
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