Question

Difficulty: EasyLinear Equations and Graphing

A line in the standard (x,y)(x,y) coordinate plane passes through the point (0,4)(0, 4) and has a slope of 33. Which of the following equations represents this line?

  1. y=3x+4y = 3x + 4Answer
  2. B
    y=4x+3y = 4x + 3
  3. C
    y=3x4y = 3x - 4
  4. D
    y=3x+4y = -3x + 4
  5. E
    y=13x+4y = \frac{1}{3}x + 4

Answer

y=3x+4y = 3x + 4
The slope-intercept form of a linear equation is y=mx+by = mx + b. Here, the slope mm is given as 33, and the y-intercept bb is given as 44 since the line crosses the y-axis at the point (0,4)(0,4). Substituting these values into the form gives the equation y=3x+4y = 3x + 4.

Step-by-Step Solution

1
Identify the slope-intercept form of a linear equation.
The slope-intercept form is y=mx+by = mx + b, where mm is the slope and bb is the yy-intercept.
To write the equation of a line, we can substitute the known slope and y-intercept into this general form.
2
Determine the values of mm and bb from the given information.
The slope m=3m = 3. The point (0,4)(0, 4) lies on the y-axis, meaning the y-intercept b=4b = 4.
The y-intercept is the y-coordinate of the point where the line crosses the y-axis, which occurs when x=0x = 0.
3
Substitute the values of mm and bb into the slope-intercept equation.
y=3x+4y = 3x + 4
Replacing mm with 33 and bb with 44 yields the equation representing the line.

Key Concept

Writing linear equations in slope-intercept form using the slope and a point.
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