Question

Difficulty: MediumRight Triangle Trigonometry (SOHCAHTOA)

In right triangle LMNLMN, the right angle is at vertex MM. The hypotenuse LNLN has a length of 2525 units. If cos(L)=725\cos(L) = \frac{7}{25}, what is the value of tan(N)\tan(N)?

  1. 724\frac{7}{24}Answer
  2. B
    247\frac{24}{7}
  3. C
    725\frac{7}{25}
  4. D
    2425\frac{24}{25}
  5. E
    257\frac{25}{7}

Answer

724\frac{7}{24}
The ratio cos(L)=725\cos(L) = \frac{7}{25} means the leg adjacent to angle LL (LMLM) is 77 units and the hypotenuse (LNLN) is 2525 units. Using the Pythagorean theorem (72+MN2=2527^2 + MN^2 = 25^2), the remaining leg MNMN is 2424 units. For angle NN, the opposite side is LM=7LM = 7 and the adjacent side is MN=24MN = 24. Thus, tan(N)=oppositeadjacent=724\tan(N) = \frac{\text{opposite}}{\text{adjacent}} = \frac{7}{24}.

Step-by-Step Solution

1
Use the definition of cosine for angle LL to identify the length of leg LMLM.
Since cos(L)=adjacenthypotenuse=LM25=725\cos(L) = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{LM}{25} = \frac{7}{25}, the length of leg LMLM is 77 units.
Cosine is defined as the ratio of the adjacent side to the hypotenuse in a right triangle.
2
Calculate the length of the remaining leg MNMN using the Pythagorean theorem.
MN=LN2LM2=25272=62549=576=24MN = \sqrt{LN^2 - LM^2} = \sqrt{25^2 - 7^2} = \sqrt{625 - 49} = \sqrt{576} = 24 units.
In a right triangle, the square of the hypotenuse equals the sum of the squares of the legs.
3
Set up the tangent ratio for angle NN.
tan(N)=opposite side to Nadjacent side to N=LMMN=724\tan(N) = \frac{\text{opposite side to } N}{\text{adjacent side to } N} = \frac{LM}{MN} = \frac{7}{24}.
Tangent is defined as the ratio of the side opposite the angle to the side adjacent to the angle.

Key Concept

Right Triangle Trigonometric Ratios (SOHCAHTOA)
Estimated Time:1m 0s
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