Question

Difficulty: MediumBasic Probability and Counting Methods

A catering service allows customers to build a custom buffet meal by selecting 11 appetizer from 44 available options, 11 main course from 55 available options, and 22 distinct side dishes from 66 available options. However, due to preparation constraints, 22 specific side dishes cannot be selected together. How many different valid buffet meal combinations can a customer choose?

  1. A
    2323
  2. B
    120120
  3. 280280Answer
  4. D
    300300
  5. E
    600600

Answer

The total number of valid buffet meal combinations is 280280.
There are 44 appetizer choices and 55 main course choices. Choosing 22 side dishes out of 66 options gives (62)=15\binom{6}{2} = 15 total pairs. Subtracting the 11 disallowed pair leaves 1414 valid side dish pairs. Multiplying these independent choices gives 4×5×14=2804 \times 5 \times 14 = 280 valid buffet menu combinations.

Step-by-Step Solution

1
Calculate the total number of ways to select 2 distinct side dishes from 6 options.
(62)=6×52×1=15\binom{6}{2} = \frac{6 \times 5}{2 \times 1} = 15 combinations.
Since the order in which the 2 side dishes are picked does not matter, combinations are used.
2
Subtract the restricted pair of side dishes from the total side dish combinations.
151=1415 - 1 = 14 valid side dish combinations.
The problem specifies that 2 specific side dishes cannot be selected together, eliminating 1 specific pair.
3
Apply the Fundamental Counting Principle to find the overall number of valid buffet menu choices.
4 (appetizers)×5 (main courses)×14 (valid side pairs)=2804 \text{ (appetizers)} \times 5 \text{ (main courses)} \times 14 \text{ (valid side pairs)} = 280.
The choices for appetizer, main course, and side dish pair are independent, so their individual number of possibilities are multiplied.

Key Concept

Fundamental Counting Principle and Combinations with Restrictions
Estimated Time:1m 15s
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