An agricultural cooperative packages a premium seed mixture containing rye grass, fescue, and bluegrass. The weight of the fescue in the mixture is pounds less than twice the weight of the rye grass. The weight of the bluegrass is pounds more than half the weight of the fescue. If the total weight of the mixture is pounds, how many pounds of bluegrass are in the mixture?
Answer: 40 pounds
Answer
The weight of the bluegrass in the mixture is 40 pounds.
By translating the given relationships into equations (, , and ), we can express all variables in terms of , yielding . Solving this gives . Substituting this back gives the weight of bluegrass as pounds.
Step-by-Step Solution
Key Concept
Translating verbal relationships into linear equations and solving a system of equations