A commercial bakery uses an automated dough divider that cuts a large batch of dough of ma… — ACT

A commercial bakery uses an automated dough divider that cuts a large batch of dough of mass $m$ kilograms into $48$ identical portioned rolls. If each portioned roll has a mass of $0.125$ kilograms, what was the total mass $m$ , in kilograms, of the original batch of dough?

A
$0.0026$
$6.00$ Answer
C
$47.875$
D
$48.125$
E
$384.00$

Answer

The total mass of the original batch of dough is

6.00

kilograms.

The scenario describes dividing a total mass

m

into

48

equal parts, where each part equals

0.125

kg. Setting up the one-step division equation

\frac{m}{48} = 0.125

and multiplying both sides by

48

gives

m = 6.00

kilograms.

Step-by-Step Solution

Define the algebraic relationship based on the problem description.

\frac{m}{48} = 0.125

Dividing the total mass

m

into

48

equal pieces yields the mass of one individual roll.

Isolate the variable

m

by performing the inverse operation.

m = 48 \times 0.125

Multiply both sides of the equation by

48

to cancel out the denominator.

Calculate the numerical product.

m = 6.00

48 \times 0.125 = 6.00

kilograms.

Key Concept

Basic Algebraic Expressions and One-Step Equations

Question

Answer

Step-by-Step Solution

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