Question

Difficulty: EasyGraphs of Trigonometric Functions

What is the period of the function f(x)=4cos(13x)f(x) = 4\cos\left(\frac{1}{3}x\right)?

  1. A
    2π3\frac{2\pi}{3}
  2. B
    2π2\pi
  3. C
    44
  4. 6π6\piAnswer
  5. E
    4π3\frac{4\pi}{3}

Answer

The period of the function is 6π6\pi.
The standard period of the cosine function y=cos(x)y = \cos(x) is 2π2\pi. For a transformed trigonometric function of the form y=Acos(Bx)y = A\cos(Bx), the period is given by the formula 2πB\frac{2\pi}{|B|}. In the function f(x)=4cos(13x)f(x) = 4\cos\left(\frac{1}{3}x\right), the coefficient of xx is B=13B = \frac{1}{3}. Dividing the standard period 2π2\pi by 13\frac{1}{3} yields a period of 2π×3=6π2\pi \times 3 = 6\pi.

Step-by-Step Solution

1
Identify the standard period of the parent cosine function and the coefficient BB of the variable xx in the given function.
The parent function is y=cos(x)y = \cos(x), which has a standard period of 2π2\pi. In the function f(x)=4cos(13x)f(x) = 4\cos\left(\frac{1}{3}x\right), the coefficient of xx is B=13B = \frac{1}{3}.
This sets up the parameters needed for the period formula Period=2πB\text{Period} = \frac{2\pi}{|B|}.
2
Substitute the value of BB into the period formula and simplify.
The period is 2π13=2π×3=6π\frac{2\pi}{\frac{1}{3}} = 2\pi \times 3 = 6\pi.
Dividing by a fraction is equivalent to multiplying by its reciprocal, which gives the final horizontal distance for one complete cycle.

Key Concept

Graphs of Trigonometric Functions
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