Question

Difficulty: HardTransformations in the Coordinate Plane

A graphic designer uses a coordinate plane to design a logo containing a triangular shape. The final image of the triangle has vertices at (3,1)(3, -1), (5,3)(5, -3), and (2,5)(2, -5). The designer created this final image by performing a 9090^\circ counterclockwise rotation of the original triangle about the origin, followed by a translation of 44 units to the right and 33 units down. What are the coordinates of the vertices of the original triangle?

  1. (2,1)(2, 1), (0,1)(0, -1), and (2,2)(-2, 2)Answer
  2. B
    (2,1)(-2, -1), (0,1)(0, 1), and (2,2)(2, -2)
  3. C
    (4,7)(-4, -7), (6,9)(-6, -9), and (8,6)(-8, -6)
  4. D
    (5,0)(5, 0), (7,2)(7, 2), and (9,1)(9, -1)
  5. E
    (1,2)(-1, -2), (1,0)(1, 0), and (2,2)(-2, 2)

Answer

The coordinates of the vertices of the original triangle are (2,1)(2, 1), (0,1)(0, -1), and (2,2)(-2, 2).
The correct answer is obtained by working backward from the final image. First, undo the translation of 44 units right and 33 units down by translating the final vertices 44 units left and 33 units up. This yields intermediate vertices (1,2)(-1, 2), (1,0)(1, 0), and (2,2)(-2, -2). Second, undo the 9090^\circ counterclockwise rotation by rotating these intermediate vertices 9090^\circ clockwise about the origin. The algebraic rule for a 9090^\circ clockwise rotation is (x,y)(y,x)(x, y) \rightarrow (y, -x). Applying this rule to (1,2)(-1, 2), (1,0)(1, 0), and (2,2)(-2, -2) gives the original coordinates (2,1)(2, 1), (0,1)(0, -1), and (2,2)(-2, 2).

Step-by-Step Solution

1
Identify the two transformations in reverse order and define their inverse operations.
The final transformation was a translation of 44 units to the right and 33 units down, so the first step in working backward is a translation of 44 units to the left and 33 units up. The initial transformation was a 9090^\circ counterclockwise rotation about the origin, so the second step in working backward is a 9090^\circ clockwise rotation about the origin.
To find the pre-image, we must apply the inverse of each transformation in the reverse order of how they were originally applied.
2
Apply the inverse translation of 44 units left and 33 units up to the final image vertices: (3,1)(3, -1), (5,3)(5, -3), and (2,5)(2, -5).
The intermediate vertices are: A(3,1)A1(34,1+3)=(1,2)A'(3, -1) \rightarrow A_1(3 - 4, -1 + 3) = (-1, 2); B(5,3)B1(54,3+3)=(1,0)B'(5, -3) \rightarrow B_1(5 - 4, -3 + 3) = (1, 0); C(2,5)C1(24,5+3)=(2,2)C'(2, -5) \rightarrow C_1(2 - 4, -5 + 3) = (-2, -2).
Undoing a translation of (+4,3)(+4, -3) requires subtracting 44 from the xx-coordinates and adding 33 to the yy-coordinates.
3
Apply the inverse rotation, a 9090^\circ clockwise rotation about the origin, to the intermediate vertices.
The rule for a 9090^\circ clockwise rotation about the origin is (x1,y1)(y1,x1)(x_1, y_1) \rightarrow (y_1, -x_1). Applying this to the intermediate vertices yields: A1(1,2)A(2,1)A_1(-1, 2) \rightarrow A(2, 1); B1(1,0)B(0,1)B_1(1, 0) \rightarrow B(0, -1); C1(2,2)C(2,2)C_1(-2, -2) \rightarrow C(-2, 2).
A 9090^\circ clockwise rotation is the inverse of a 9090^\circ counterclockwise rotation, which reverses the coordinates and changes the sign of the new yy-coordinate.

Key Concept

Finding the pre-image of a figure under composite transformations in the coordinate plane by applying inverse transformations in reverse order.
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