Question

Difficulty: MediumParallel and Perpendicular Lines

In the standard (x,y)(x, y) coordinate plane, line L1L_1 passes through the points (2,5)(2, 5) and (6,3)(6, -3). A second line, L2L_2, is perpendicular to L1L_1 and intersects L1L_1 at its yy-intercept. What is the xx-coordinate of the xx-intercept of L2L_2?

Answer: -18

Answer

The xx-coordinate of the xx-intercept of L2L_2 is 18-18.
First, the slope of L1L_1 is calculated as 2-2 using the slope formula. Substituting one of the points into the slope-intercept form gives the yy-intercept of L1L_1 as (0,9)(0, 9). Since L2L_2 is perpendicular to L1L_1, its slope is the negative reciprocal of 2-2, which is 12\frac{1}{2}. Since L2L_2 shares the yy-intercept (0,9)(0, 9), its equation is y=12x+9y = \frac{1}{2}x + 9. Setting y=0y = 0 to find the xx-intercept gives x=18x = -18.

Step-by-Step Solution

1
Calculate the slope of line L1L_1.
The slope of L1L_1 is 2-2.
Using the slope formula m=y2y1x2x1m = \frac{y_2 - y_1}{x_2 - x_1} with the given points (2,5)(2, 5) and (6,3)(6, -3) yields m1=3562=2m_1 = \frac{-3 - 5}{6 - 2} = -2.
2
Find the yy-intercept of L1L_1.
The yy-intercept is (0,9)(0, 9).
Substituting m=2m = -2 and the coordinates of (2,5)(2, 5) into the slope-intercept equation y=mx+by = mx + b gives 5=2(2)+b5 = -2(2) + b, which simplifies to b=9b = 9.
3
Find the slope of the perpendicular line, L2L_2.
The slope of L2L_2 is 12\frac{1}{2}.
Perpendicular lines have slopes that are negative reciprocals of each other. The negative reciprocal of 2-2 is 12\frac{1}{2}.
4
Determine the equation of L2L_2 and calculate its xx-intercept.
The xx-coordinate of the xx-intercept of L2L_2 is 18-18.
Since L2L_2 passes through the yy-intercept (0,9)(0, 9), its equation is y=12x+9y = \frac{1}{2}x + 9. Setting y=0y = 0 to find the xx-intercept yields 0=12x+90 = \frac{1}{2}x + 9, which solves to x=18x = -18.

Key Concept

Determining the equation and intercepts of a line perpendicular to a given line that passes through a specific shared point.
Estimated Time:1m 30s
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