Question

Difficulty: EasyLogarithmic and Exponential Expressions and Equations

If 32x1=273^{2x - 1} = 27, what is the value of xx?

Answer: 2

Answer

The value of xx is 22.
Rewriting 2727 as 333^3 gives the equation 32x1=333^{2x - 1} = 3^3. Equating the exponents yields 2x1=32x - 1 = 3, which solves to x=2x = 2.

Step-by-Step Solution

1
Rewrite the right side of the equation with a base of 33.
32x1=333^{2x - 1} = 3^3
Expressing both sides of the equation with a common base allows for direct comparison of the exponents.
2
Set the exponents equal to each other.
2x1=32x - 1 = 3
Since the bases are both 33, their exponents must be equal for the expressions to be equal.
3
Solve the linear equation for xx.
x=2x = 2
Adding 11 to both sides gives 2x=42x = 4. Dividing both sides by 22 results in x=2x = 2.

Key Concept

Solving exponential equations by expressing both sides with a common base
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