Question

Difficulty: MediumQuadratic Equations and the Quadratic Formula

In the quadratic equation 2x211x+c=02x^2 - 11x + c = 0, where cc is a constant, the ratio of the two real solutions is 3:83:8. What is the value of cc?

Answer: 12

Answer

The value of the constant cc is 1212.
The correct answer is 1212. By representing the roots in the ratio of 3:83:8 as 3r3r and 8r8r, Vieta's formula for the sum of roots (ba-\frac{b}{a}) gives 3r+8r=112    11r=5.5    r=0.53r + 8r = -\frac{-11}{2} \implies 11r = 5.5 \implies r = 0.5. The actual roots are therefore 1.51.5 and 44. Using Vieta's formula for the product of roots (ca\frac{c}{a}) gives (1.5)(4)=c2    6=c2    c=12(1.5)(4) = \frac{c}{2} \implies 6 = \frac{c}{2} \implies c = 12.

Step-by-Step Solution

1
Represent the roots using the given ratio.
Let the two roots of the quadratic equation be 3r3r and 8r8r.
The ratio of the two solutions is specified as 3:83:8.
2
Apply Vieta's formula for the sum of roots to find the ratio multiplier rr.
3r+8r=112    11r=5.5    r=0.53r + 8r = -\frac{-11}{2} \implies 11r = 5.5 \implies r = 0.5.
For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the sum of the roots is given by ba-\frac{b}{a}.
3
Determine the numerical values of the two roots.
The roots are 3(0.5)=1.53(0.5) = 1.5 and 8(0.5)=48(0.5) = 4.
Substitute the value of r=0.5r = 0.5 back into the expressions for the roots.
4
Apply Vieta's formula for the product of roots to solve for the constant cc.
(1.5)(4)=c2    6=c2    c=12(1.5)(4) = \frac{c}{2} \implies 6 = \frac{c}{2} \implies c = 12.
For a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0, the product of the roots is given by ca\frac{c}{a}.

Key Concept

Vieta's formulas and the relationship between the roots and coefficients of a quadratic equation

Alternative Method

Alternatively, you can express the roots using the quadratic formula: x=11±1218c4x = \frac{11 \pm \sqrt{121 - 8c}}{4}. Since the ratio of the smaller root to the larger root is 3:83:8, we set up the equation: 111218c11+1218c=38\frac{11 - \sqrt{121 - 8c}}{11 + \sqrt{121 - 8c}} = \frac{3}{8}. Cross-multiplying gives 8(111218c)=3(11+1218c)    8881218c=33+31218c    55=111218c    5=1218c    25=1218c    8c=96    c=128(11 - \sqrt{121 - 8c}) = 3(11 + \sqrt{121 - 8c}) \implies 88 - 8\sqrt{121 - 8c} = 33 + 3\sqrt{121 - 8c} \implies 55 = 11\sqrt{121 - 8c} \implies 5 = \sqrt{121 - 8c} \implies 25 = 121 - 8c \implies 8c = 96 \implies c = 12.
Estimated Time:1m 30s
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