Question

Difficulty: MediumComplex Numbers and Operations

Let ii be the imaginary unit such that i2=−1i^2 = -1. What is the simplified form of the expression (1+2i)2(3−i)(1 + 2i)^2(3 - i)?

  1. A
    −9+3i-9 + 3i
  2. −5+15i-5 + 15iAnswer
  3. C
    19+7i19 + 7i
  4. D
    −13+15i-13 + 15i
  5. E
    50i50i

Answer

−5+15i-5 + 15i
The correct answer is −5+15i-5 + 15i. We first expand the squared binomial (1+2i)2(1 + 2i)^2, which results in 1+4i+4i21 + 4i + 4i^2. Substituting i2=−1i^2 = -1 yields −3+4i-3 + 4i. We then multiply this by the second binomial (3−i)(3 - i) to get −9+3i+12i−4i2-9 + 3i + 12i - 4i^2. Substituting i2=−1i^2 = -1 one more time and combining like terms leads to the final simplified result of −5+15i-5 + 15i.

Step-by-Step Solution

1
Expand the squared binomial (1+2i)2(1 + 2i)^2
1+4i+4i21 + 4i + 4i^2
Before multiplying by the second binomial, we must apply the exponent to the first binomial according to the order of operations.
2
Substitute i2=−1i^2 = -1 to simplify the expression from Step 1
−3+4i-3 + 4i
Since i2=−1i^2 = -1, the term 4i24i^2 becomes 4(−1)=−44(-1) = -4, and combining the real parts gives 1−4=−31 - 4 = -3.
3
Multiply the simplified term by (3−i)(3 - i) using the FOIL method
−9+3i+12i−4i2-9 + 3i + 12i - 4i^2
We distribute each term of the first binomial into the second binomial: (−3)(3)=−9(-3)(3) = -9, (−3)(−i)=3i(-3)(-i) = 3i, (4i)(3)=12i(4i)(3) = 12i, and (4i)(−i)=−4i2(4i)(-i) = -4i^2.
4
Simplify the resulting expression by combining like terms and substituting i2=−1i^2 = -1
−5+15i-5 + 15i
Combining the imaginary parts gives 3i+12i=15i3i + 12i = 15i. Substituting i2=−1i^2 = -1 into −4i2-4i^2 gives −4(−1)=+4-4(-1) = +4. Finally, combining the real parts yields −9+4=−5-9 + 4 = -5.

Key Concept

Simplification of complex expressions involving binomial squaring and multiplication under the definition i2=−1i^2 = -1.
Estimated Time:1m 30s
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