Question

Difficulty: Very hardEvaluating Algebraic Expressions

If a=27a = -27, b=14b = -\frac{1}{4}, and c=2c = -2, what is the value of the algebraic expression a4/3b2c5a^{-4/3} - b^{-2} \cdot c^{-5}?

  1. A
    79162-\frac{79}{162}
  2. B
    79162\frac{79}{162}
  3. 83162\frac{83}{162}Answer
  4. D
    1632\frac{163}{2}
  5. E
    12952592\frac{1295}{2592}

Answer

The correct value of the algebraic expression is 83162\frac{83}{162}.
Evaluating each term of the expression with the given values yields: a4/3=181a^{-4/3} = \frac{1}{81}, b2=16b^{-2} = 16, and c5=132c^{-5} = -\frac{1}{32}. Applying the order of operations, we multiply 1616 by 132-\frac{1}{32} first to obtain 12-\frac{1}{2}. We then subtract this product from 181\frac{1}{81}, which simplifies to 181+12=83162\frac{1}{81} + \frac{1}{2} = \frac{83}{162}.

Step-by-Step Solution

1
Substitute the given values of aa, bb, and cc into the algebraic expression.
The expression is written as (27)4/3(14)2(2)5(-27)^{-4/3} - (-\frac{1}{4})^{-2} \cdot (-2)^{-5}.
This establishes the numerical expression to be evaluated.
2
Evaluate the first term, (27)4/3(-27)^{-4/3}.
(27)4/3=1(27)4/3=1((27)1/3)4=1(3)4=181(-27)^{-4/3} = \frac{1}{(-27)^{4/3}} = \frac{1}{((-27)^{1/3})^4} = \frac{1}{(-3)^4} = \frac{1}{81}.
A negative exponent indicates a reciprocal, and a fractional exponent of 4/34/3 indicates taking the cube root and then raising to the fourth power.
3
Evaluate the second term, (14)2(-\frac{1}{4})^{-2}.
(14)2=(4)2=16(-\frac{1}{4})^{-2} = (-4)^2 = 16.
Raising a fraction to a negative integer power is equivalent to raising its reciprocal to the corresponding positive integer power.
4
Evaluate the third term, (2)5(-2)^{-5}.
(2)5=1(2)5=132(-2)^{-5} = \frac{1}{(-2)^5} = -\frac{1}{32}.
Evaluating a negative base raised to an odd negative power results in a negative unit fraction.
5
Substitute the evaluated terms back into the original expression and apply the order of operations.
E=18116(132)=181(1632)=181+12=2+81162=83162E = \frac{1}{81} - 16 \cdot \left(-\frac{1}{32}\right) = \frac{1}{81} - \left(-\frac{16}{32}\right) = \frac{1}{81} + \frac{1}{2} = \frac{2 + 81}{162} = \frac{83}{162}.
Multiplication must be performed before subtraction according to standard mathematical order of operations.

Key Concept

Evaluating expressions containing multiple variables with fractional exponents, negative bases, and standard order of operations.
Estimated Time:2m 0s
Rate this question