Question

Difficulty: MediumBasic Algebraic Expressions and One-Step Equations

A freight shipping company calculates the total fuel consumption, CC in gallons, for a cargo vessel using the equation C=45hC = 45h, where hh represents the number of hours the vessel operates at cruising speed. If the vessel consumed a total of 3,1503,150 gallons of fuel on a recent journey, for how many hours did the vessel operate at cruising speed?

  1. 7070Answer
  2. B
    7575
  3. C
    3,1053,105
  4. D
    3,1953,195
  5. E
    141,750141,750

Answer

70 hours
To find the number of hours hh, substitute 3,1503,150 for CC in the equation C=45hC = 45h, yielding 3,150=45h3,150 = 45h. Dividing both sides by 4545 gives h=70h = 70. Therefore, the vessel operated at cruising speed for 7070 hours.

Step-by-Step Solution

1
Identify the given values and formula from the problem statement.
Formula: C=45hC = 45h, with total fuel consumption C=3,150C = 3,150 gallons.
This sets up the linear one-step equation to solve for the unknown operating time hh.
2
Substitute C=3,150C = 3,150 into the equation.
3,150=45h3,150 = 45h
Replacing the variable CC with its given numeric value leaves a one-step multiplication equation in terms of hh.
3
Isolate hh by performing the inverse operation.
h=3,15045=70h = \frac{3,150}{45} = 70
Dividing both sides of the equation by 4545 isolates hh to find the number of hours.

Key Concept

Solving One-Step Multiplication Equations
Estimated Time:1m 0s
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