Solving Linear Equations

43 questions

Question 21Question

A storage tank contains 1818 gallons of water and is being filled at a constant rate of 23\frac{2}{3} gallons per minute. A second storage tank contains 3333 gallons of water and is being drained at a constant rate of 56\frac{5}{6} gallons per minute. If both tanks begin their processes at the same time, they will contain the same amount of water after mm minutes. What is the value of 2m+32m + 3?

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Answer: 23

Answer

23
The correct answer is 23. By representing the volume of the first tank as 18+23m18 + \frac{2}{3}m and the second tank as 3356m33 - \frac{5}{6}m, setting them equal gives 18+23m=3356m18 + \frac{2}{3}m = 33 - \frac{5}{6}m. Solving this equation by finding a common denominator for the fraction coefficients yields 96m=15\frac{9}{6}m = 15, which simplifies to 32m=15\frac{3}{2}m = 15, and thus m=10m = 10. Substituting m=10m = 10 into the expression 2m+32m + 3 results in 2(10)+3=232(10) + 3 = 23.

Step-by-Step Solution

1
Set up the equation representing the water volume in both tanks over time.
18+23m=3356m18 + \frac{2}{3}m = 33 - \frac{5}{6}m
The first tank starts with 1818 gallons and increases by 23\frac{2}{3} gallons per minute, while the second starts with 3333 gallons and decreases by 56\frac{5}{6} gallons per minute. We set their volumes equal to find when they contain the same amount.
2
Isolate the variable terms on one side and the constant terms on the other side.
23m+56m=3318\frac{2}{3}m + \frac{5}{6}m = 33 - 18
Adding 56m\frac{5}{6}m to both sides and subtracting 1818 from both sides groups like terms together.
3
Find a common denominator to add the fraction coefficients.
46m+56m=1596m=1532m=15\frac{4}{6}m + \frac{5}{6}m = 15 \Rightarrow \frac{9}{6}m = 15 \Rightarrow \frac{3}{2}m = 15
A common denominator of 66 is used to add the fractions 23\frac{2}{3} and 56\frac{5}{6}.
4
Solve for mm by multiplying both sides by the reciprocal of the coefficient.
m=15×23=10m = 15 \times \frac{2}{3} = 10
Multiplying by 23\frac{2}{3} isolates mm on the left side.
5
Evaluate the expression 2m+32m + 3 using the value of mm.
2(10)+3=20+3=232(10) + 3 = 20 + 3 = 23
Substitute m=10m = 10 into the expression and follow the correct order of operations (multiply first, then add).

Key Concept

Solving linear equations with fractional coefficients and translating word problems into algebraic equations.
Question 22Question

If 23(3x4)14(x+2)=223\frac{2}{3}(3x - 4) - \frac{1}{4}(x + 2) = \frac{22}{3}, what is the value of 3x+23x + 2?

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Answer: 20

Answer

The correct answer is 20, which is the value of the expression 3x+23x + 2 when x=6x = 6.
The value of the expression 3x+23x + 2 is 20. Solving the linear equation 23(3x4)14(x+2)=223\frac{2}{3}(3x - 4) - \frac{1}{4}(x + 2) = \frac{22}{3} yields x=6x = 6. Substituting x=6x = 6 into 3x+23x + 2 gives 3(6)+2=203(6) + 2 = 20.

Step-by-Step Solution

1
Multiply the entire equation by the least common multiple of the denominators (12).
8(3x4)3(x+2)=888(3x - 4) - 3(x + 2) = 88
This clears the fractions to make solving the equation simpler.
2
Distribute the coefficients to remove parentheses.
24x323x6=8824x - 32 - 3x - 6 = 88
This allows like terms to be grouped together.
3
Combine like terms on the left side of the equation.
21x38=8821x - 38 = 88
Simplifies the equation to prepare for isolating the variable.
4
Add 38 to both sides of the equation.
21x=12621x = 126
Isolates the variable term on one side of the equation.
5
Divide both sides by 21 to solve for xx.
x=6x = 6
Finds the value of the variable xx.
6
Substitute x=6x = 6 into the target expression 3x+23x + 2.
3(6)+2=203(6) + 2 = 20
Calculates the final requested value.

Key Concept

Solving multi-step linear equations with fractions and evaluating algebraic expressions.
Question 23Question

For a certain real number xx, the equation 34(x3)13(2x+5)=2\frac{3}{4}(x - 3) - \frac{1}{3}(2x + 5) = -2 is true. What is the value of 2x52x - 5?

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Answer: 41

Answer

The value of the expression 2x52x - 5 is 41.
Solving the linear equation by multiplying both sides by the least common denominator of 12 yields the simplified equation 9(x3)4(2x+5)=249(x - 3) - 4(2x + 5) = -24. Expanding the terms gives 9x278x20=249x - 27 - 8x - 20 = -24, which simplifies to x47=24x - 47 = -24. Adding 47 to both sides gives x=23x = 23. Finally, evaluating the expression 2x52x - 5 for x=23x = 23 results in 2(23)5=412(23) - 5 = 41.

Step-by-Step Solution

1
Multiply both sides of the equation by the least common denominator of 12 to eliminate fractions.
9(x3)4(2x+5)=249(x - 3) - 4(2x + 5) = -24
Multiplying by the LCD clears all fractional coefficients, making the equation easier to solve.
2
Distribute the constants and expand the terms on the left side of the equation.
9x278x20=249x - 27 - 8x - 20 = -24
Applying the distributive property removes the parentheses.
3
Combine like terms on the left side of the equation.
x47=24x - 47 = -24
Simplifying the equation makes it easier to isolate the variable xx.
4
Isolate the variable xx by adding 47 to both sides of the equation.
x=23x = 23
This determines the value of the unknown variable xx.
5
Substitute x=23x = 23 into the target expression 2x52x - 5.
4141
The question asks for the value of the expression 2x52x - 5, not just the value of xx.

Key Concept

Solving multi-step linear equations with fractional coefficients by clearing the denominators and then evaluating algebraic expressions.

Alternative Method

Instead of multiplying by the LCD first, distribute the fractions directly: 34x9423x53=2\frac{3}{4}x - \frac{9}{4} - \frac{2}{3}x - \frac{5}{3} = -2. Combine the xx terms: (3423)x=112x(\frac{3}{4} - \frac{2}{3})x = \frac{1}{12}x. Combine the constant terms: 9453=27122012=4712-\frac{9}{4} - \frac{5}{3} = -\frac{27}{12} - \frac{20}{12} = -\frac{47}{12}. This gives the equation 112x4712=2\frac{1}{12}x - \frac{47}{12} = -2. Add 4712\frac{47}{12} to both sides: 112x=2+4712=2412+4712=2312\frac{1}{12}x = -2 + \frac{47}{12} = -\frac{24}{12} + \frac{47}{12} = \frac{23}{12}. Multiply by 12 to get x=23x = 23, then evaluate 2x5=412x - 5 = 41.
Estimated Time:1m 30s
Question 24Question

In a chemistry laboratory, a beaker contains a mixture of water and acid. The volume of water in the beaker is 33 liters more than twice the volume of acid. After 55 liters of water are added to the beaker, the ratio of the volume of water to the volume of acid is 55 to 22. If no acid was added or removed, what was the initial volume of water, in liters, in the beaker?

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Answer: 35

Answer

35
The correct answer of 35 liters is found by setting up the linear equation where the initial volume of acid is aa and the initial volume of water is 2a+32a + 3. Adding 5 liters of water gives 2a+82a + 8 liters of water. Setting the ratio of water to acid to 52\frac{5}{2} and solving gives a=16a = 16. Finally, substituting a=16a = 16 into the expression for the initial volume of water (2a+32a + 3) yields 35 liters.

Step-by-Step Solution

1
Define variables for the initial volumes of acid and water based on the given relationships.
Let aa be the initial volume of acid in liters. The initial volume of water is 2a+32a + 3 liters.
This translates the statement 'the volume of water is 3 liters more than twice the volume of acid' into algebraic expressions.
2
Set up a linear equation representing the ratio after adding 5 liters of water.
The new volume of water is (2a+3)+5=2a+8(2a + 3) + 5 = 2a + 8 liters. The ratio of water to acid is 2a+8a=52\frac{2a + 8}{a} = \frac{5}{2}.
This uses the new state of the mixture to form an equation that can be solved for aa.
3
Solve the linear equation for aa by cross-multiplying and isolating the variable.
2(2a+8)=5a    4a+16=5a    a=162(2a + 8) = 5a \implies 4a + 16 = 5a \implies a = 16.
Cross-multiplication removes the fractions and allows for standard term isolation.
4
Calculate the initial volume of water.
Initial water volume = 2a+3=2(16)+3=352a + 3 = 2(16) + 3 = 35 liters.
The question asks for the initial volume of water, which is represented by 2a+32a + 3, not the volume of acid aa.

Key Concept

Solving linear equations in one variable derived from word problems.

Alternative Method

Instead of solving algebraically, one could test the answer choices. For example, testing 35 liters of water means the initial acid is (353)/2=16(35 - 3) / 2 = 16 liters. Adding 5 liters of water gives 40 liters of water. The ratio of water to acid is 40:1640 : 16, which simplifies to 5:25 : 2. This confirms 35 is correct.
Estimated Time:1m 30s
Question 25Question

If the equation 25(x4)+13(2x+k)=7\frac{2}{5}(x - 4) + \frac{1}{3}(2x + k) = 7 is true when x=9x = 9, what is the value of kk?

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Answer: 3-3

Answer

3-3
Substituting x=9x = 9 into the equation gives 25(94)+13(2(9)+k)=7\frac{2}{5}(9 - 4) + \frac{1}{3}(2(9) + k) = 7. Simplifying the terms yields 2+18+k3=72 + \frac{18 + k}{3} = 7. Subtracting 2 from both sides results in 18+k3=5\frac{18 + k}{3} = 5. Multiplying by 3 gives 18+k=1518 + k = 15. Subtracting 18 from both sides gives k=3k = -3.

Step-by-Step Solution

1
Substitute x=9x = 9 into the given equation.
25(94)+13(2(9)+k)=7\frac{2}{5}(9 - 4) + \frac{1}{3}(2(9) + k) = 7
We are given that the equation is true when x=9x = 9.
2
Simplify the operations inside the parentheses.
2+18+k3=72 + \frac{18 + k}{3} = 7
Simplifying 25(5)\frac{2}{5}(5) gives 2, and 2(9)2(9) gives 18.
3
Subtract 2 from both sides of the equation.
18+k3=5\frac{18 + k}{3} = 5
Isolating the fraction term simplifies the equation.
4
Multiply both sides by 3.
18+k=1518 + k = 15
Clearing the denominator allows us to isolate the variable kk.
5
Subtract 18 from both sides of the equation.
k=3k = -3
This isolates kk to find its value.

Key Concept

Solving linear equations in one variable by substitution and simplification
Question 26Question

A landscaping company purchases bags of grass seed for 3030 each and bags of fertilizer for 1818 each. For a large project, the company purchased 22 fewer than 1.51.5 times as many bags of fertilizer as bags of grass seed. If the total cost of the grass seed and fertilizer was 420420, how many bags of fertilizer did the company purchase?

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Answer: 10

Answer

The company purchased 10 bags of fertilizer.
The correct answer is 10. By writing the number of fertilizer bags as f=1.5g2f = 1.5g - 2 and substituting this expression into the total cost equation 30g+18f=42030g + 18f = 420, we get 30g+18(1.5g2)=42030g + 18(1.5g - 2) = 420. Simplifying the expression leads to 57g36=42057g - 36 = 420, which yields g=8g = 8. Substituting g=8g = 8 back into the relationship for ff gives f=1.5(8)2=10f = 1.5(8) - 2 = 10.

Step-by-Step Solution

1
Define variables for the unknown quantities.
Let gg represent the number of grass seed bags and ff represent the number of fertilizer bags.
Setting up variables is the first step in translating the word problem into solvable algebraic equations.
2
Translate the relationship between the quantities of bags into an equation.
f=1.5g2f = 1.5g - 2
The problem states that the number of fertilizer bags purchased is 2 fewer than 1.5 times the number of grass seed bags purchased.
3
Write the total cost equation using the prices and variables.
30g+18f=42030g + 18f = 420
The total cost of 420420 is the sum of the cost of the grass seed (3030 per bag) and the fertilizer (1818 per bag).
4
Substitute the equation from Step 2 into the cost equation from Step 3.
30g+18(1.5g2)=42030g + 18(1.5g - 2) = 420
Substituting allows us to solve a single linear equation with one variable.
5
Distribute the 18 through the parentheses and combine like terms.
57g36=42057g - 36 = 420
Distributing gives 18×1.5g=27g18 \times 1.5g = 27g and 18×2=3618 \times -2 = -36. Combining 30g30g and 27g27g yields 57g57g.
6
Isolate the variable term by adding 36 to both sides of the equation.
57g=45657g = 456
To solve for gg, we must isolate the term containing the variable.
7
Divide both sides by 57 to find the value of gg.
g=8g = 8
This division yields the number of grass seed bags purchased.
8
Substitute the value of gg back into the relation for ff to find the final answer.
f=1.5(8)2=10f = 1.5(8) - 2 = 10
The question asks for the number of fertilizer bags (ff), not grass seed bags (gg).

Key Concept

Solving a linear equation by substitution and distributing across linear terms.
Estimated Time:1m 30s
Question 27Question

For a certain real number xx, the equation 0.4(3x5)0.15(2x+8)=1.30.4(3x - 5) - 0.15(2x + 8) = 1.3 is true. What is the value of 4x34x - 3?

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Answer: 17

Answer

The value of the expression is 17.
Distributing the decimals results in 1.2x20.3x1.2=1.31.2x - 2 - 0.3x - 1.2 = 1.3. Combining like terms yields 0.9x3.2=1.30.9x - 3.2 = 1.3. Adding 3.23.2 to both sides results in 0.9x=4.50.9x = 4.5, which simplifies to x=5x = 5 after dividing by 0.90.9. Substituting x=5x = 5 into the expression 4x34x - 3 gives 4(5)3=174(5) - 3 = 17.

Step-by-Step Solution

1
Distribute the decimal factors through the parentheses on the left side of the equation.
1.2x20.3x1.2=1.31.2x - 2 - 0.3x - 1.2 = 1.3
To eliminate the parentheses and set up terms for simplification.
2
Combine the variable terms and constant terms on the left side of the equation.
0.9x3.2=1.30.9x - 3.2 = 1.3
To group like terms and simplify the equation.
3
Isolate the variable term by adding 3.23.2 to both sides of the equation.
0.9x=4.50.9x = 4.5
To gather all constant terms on the right side of the equation.
4
Divide both sides of the equation by 0.90.9 to solve for xx.
x=5x = 5
To find the numerical value of the variable.
5
Substitute the value of xx into the requested expression 4x34x - 3.
4(5)3=174(5) - 3 = 17
To evaluate the specific expression requested by the question.

Key Concept

Solving multi-step linear equations with decimals and evaluating algebraic expressions
Question 28Question

A fitness tracker records a user's daily steps. On Monday, the user walked a certain number of steps. On Tuesday, they walked 1.51.5 times the number of steps they walked on Monday. On Wednesday, they walked 2,5002,500 fewer steps than they did on Tuesday. If the user walked a total of 21,50021,500 steps over these three days, how many steps did they walk on Monday?

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Answer: 6,000

Answer

6,000
The correct answer is 6,0006,000. By letting xx represent the steps on Monday, we express Tuesday's steps as 1.5x1.5x and Wednesday's steps as 1.5x2,5001.5x - 2,500. Summing these expressions gives the equation x+1.5x+1.5x2,500=21,500x + 1.5x + 1.5x - 2,500 = 21,500. Combining like terms yields 4x2,500=21,5004x - 2,500 = 21,500. Adding 2,5002,500 to both sides gives 4x=24,0004x = 24,000, and dividing by 44 results in x=6,000x = 6,000.

Step-by-Step Solution

1
Define the variable and write expressions for each day's steps.
Let xx be the number of steps walked on Monday. Tuesday's steps are 1.5x1.5x, and Wednesday's steps are 1.5x2,5001.5x - 2,500.
This translates the word problem statements into algebraic terms using a single variable.
2
Set up the linear equation representing the total steps.
x+1.5x+(1.5x2,500)=21,500x + 1.5x + (1.5x - 2,500) = 21,500
The sum of the steps over the three days must equal the given total of 21,50021,500 steps.
3
Combine like terms and solve for xx.
4x2,500=21,5004x=24,000x=6,0004x - 2,500 = 21,500 \Rightarrow 4x = 24,000 \Rightarrow x = 6,000
Simplifying the equation isolates the variable to find Monday's step count.

Key Concept

Formulating and solving a single-variable linear equation from a word problem context.
Estimated Time:1m 15s
Question 29Question

A delivery drone starts a flight with a battery charge of 95%95\%. The battery charge decreases at a constant rate of 1.5%1.5\% per minute of flight time. During the flight, the drone lands on a charging station for 1515 minutes, during which its battery charge increases at a constant rate of 2.4%2.4\% per minute. After this charging period, the drone resumes its flight. If the drone ends its flight with a battery charge of 65%65\%, and its total flight time (excluding the time spent charging) was tt minutes, what is the value of tt?

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Answer: 44

Answer

44
The correct answer is found by setting up a linear equation that models the drone's battery charge changes. The drone starts with 95%95\% battery, loses 1.5%1.5\% per minute for tt minutes, and gains 36%36\% from charging (15×2.4%15 \times 2.4\%). Setting this equal to the final charge of 65%65\% gives the equation 951.5t+36=6595 - 1.5t + 36 = 65. Simplifying gives 1311.5t=65131 - 1.5t = 65, which leads to 1.5t=66-1.5t = -66 and t=44t = 44.

Step-by-Step Solution

1
Calculate the total percentage of battery charge gained while charging.
36%36\%
The drone charges at a rate of 2.4%2.4\% per minute for 1515 minutes, so the total gain is 15×2.4%=36%15 \times 2.4\% = 36\%.
2
Set up a linear equation for the final battery charge.
951.5t+36=6595 - 1.5t + 36 = 65
The final battery charge (65%65\%) is the initial charge (95%95\%) minus the battery consumed during flight (1.5%1.5\% per minute for tt minutes) plus the charge gained (36%36\%).
3
Combine constant terms on the left side of the equation.
1311.5t=65131 - 1.5t = 65
Adding 9595 and 3636 simplifies the expression on the left side.
4
Isolate the variable term by subtracting 131131 from both sides.
1.5t=66-1.5t = -66
Subtracting 131131 from both sides leaves only the variable term on the left.
5
Divide both sides by 1.5-1.5 to solve for tt.
t=44t = 44
Dividing 66-66 by 1.5-1.5 isolates tt to find the total flight time.

Key Concept

Solving linear equations in a real-world context by setting up an algebraic equation.
Estimated Time:1m 30s
Question 30Question

An online bookstore offers two subscription options for downloading e-books. Store A charges a monthly membership fee of 6.006.00 plus 1.251.25 per e-book download. Store B has no membership fee and charges 2.752.75 per e-book download. A customer downloads the same number of e-books from each store in a single month and spends a total of 46.0046.00 across both stores. How many e-books did the customer download from each store?

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Answer: 10

Answer

10 e-books from each store
The correct answer represents the number of downloads from each store that satisfies the total cost equation. Let xx represent the number of books downloaded from each store. The cost at Store A is 6.00+1.25x6.00 + 1.25x and the cost at Store B is 2.75x2.75x. Since the total spent is 46.0046.00, we write the equation (6.00+1.25x)+2.75x=46.00(6.00 + 1.25x) + 2.75x = 46.00. Combining like terms gives 6.00+4.00x=46.006.00 + 4.00x = 46.00. Subtracting 6.006.00 from both sides gives 4.00x=40.004.00x = 40.00, and dividing by 4.004.00 yields x=10x = 10.

Step-by-Step Solution

1
Define the variable and write the expressions for the cost of each store.
Let xx be the number of e-books downloaded from each store. Store A cost is 6.00+1.25x6.00 + 1.25x, and Store B cost is 2.75x2.75x.
Establishing algebraic expressions represents the verbal statements mathematically.
2
Set up the total cost equation by summing the costs of both stores and setting it equal to the total spent.
(6.00+1.25x)+2.75x=46.00(6.00 + 1.25x) + 2.75x = 46.00
The customer spends a combined total of 46.0046.00 across both bookstores.
3
Combine like terms and solve for the variable xx.
6.00+4.00x=46.00    4.00x=40.00    x=106.00 + 4.00x = 46.00 \implies 4.00x = 40.00 \implies x = 10
Isolating the variable determines the number of e-books downloaded from each store.

Key Concept

Solving linear equations in one variable derived from real-world scenarios.
Estimated Time:1m 30s
Question 31Question

A technician uses a linear model to estimate the time, tt hours, required to complete a project. The estimate satisfies the equation:

23(t12)+56(t+6)=18\frac{2}{3}(t - 12) + \frac{5}{6}(t + 6) = 18

What is the value of tt?

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Answer: 14

Answer

The value of tt is 1414.
To solve the linear equation, we first multiply all terms by the least common multiple of the denominators, which is 66. This simplifies the equation to 4(t12)+5(t+6)=1084(t - 12) + 5(t + 6) = 108. Distributing the terms gives 4t48+5t+30=1084t - 48 + 5t + 30 = 108. Combining like terms yields 9t18=1089t - 18 = 108. Adding 1818 to both sides gives 9t=1269t = 126. Finally, dividing by 99 gives t=14t = 14.

Step-by-Step Solution

1
Multiply both sides of the equation by 66 to eliminate the denominators.
4(t12)+5(t+6)=1084(t - 12) + 5(t + 6) = 108
Multiplying by the least common multiple of the denominators clears the fractions, making the linear equation easier to solve.
2
Apply the distributive property to expand the terms.
4t48+5t+30=1084t - 48 + 5t + 30 = 108
Distributing the constants allows us to group like terms.
3
Combine the variable terms and the constant terms on the left side.
9t18=1089t - 18 = 108
Simplifying the expression is a necessary step before isolating the variable.
4
Add 1818 to both sides of the equation.
9t=1269t = 126
Adding the constant to both sides isolates the variable term on the left side.
5
Divide both sides of the equation by 99 to solve for tt.
t=14t = 14
Dividing by the coefficient of the variable yields the final solution.

Key Concept

Solving linear equations with fractional coefficients by clearing denominators and isolating the variable.
Question 32Question

A local community garden allocates a plot of land for different types of vegetables. Tomatoes occupy 25\frac{2}{5} of the total area, peppers occupy 13\frac{1}{3} of the total area, and the remaining 80 square feet are planted with herbs. What is the total area, in square feet, of the community garden plot?

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Answer: 300

Answer

300 square feet
Let xx be the total area of the garden plot. Since the garden is divided into tomatoes (25\frac{2}{5} of the total area), peppers (13\frac{1}{3} of the total area), and herbs (8080 square feet), the sum of these parts equals the total area: 25x+13x+80=x\frac{2}{5}x + \frac{1}{3}x + 80 = x. Finding a common denominator of 15 for the fractions gives 615x+515x+80=x\frac{6}{15}x + \frac{5}{15}x + 80 = x, which simplifies to 1115x+80=x\frac{11}{15}x + 80 = x. Subtracting 1115x\frac{11}{15}x from both sides yields 80=415x80 = \frac{4}{15}x. Multiplying both sides by the reciprocal 154\frac{15}{4} gives x=80×154=300x = 80 \times \frac{15}{4} = 300 square feet.

Step-by-Step Solution

1
Define the variable and translate the given fractions and numbers into an equation. Let xx represent the total area of the garden plot.
25x+13x+80=x\frac{2}{5}x + \frac{1}{3}x + 80 = x
The sum of the areas of the tomato plot, the pepper plot, and the herb plot must equal the total area of the garden.
2
Find a common denominator to combine the fractional coefficients of xx. The least common multiple of 5 and 3 is 15. Convert 25\frac{2}{5} and 13\frac{1}{3} to fractions with a denominator of 15.
615x+515x+80=x    1115x+80=x\frac{6}{15}x + \frac{5}{15}x + 80 = x \implies \frac{11}{15}x + 80 = x
Combining like terms simplifies the expression to help isolate the variable.
3
Subtract 1115x\frac{11}{15}x from both sides of the equation to group all xx terms on one side.
80=x1115x    80=415x80 = x - \frac{11}{15}x \implies 80 = \frac{4}{15}x
This isolates the constant term on one side of the equation.
4
Multiply both sides of the equation by the reciprocal of 415\frac{4}{15}, which is 154\frac{15}{4}, to solve for xx.
x=80×154=20×15=300x = 80 \times \frac{15}{4} = 20 \times 15 = 300
This yields the value of the total area of the garden plot.

Key Concept

Solving linear equations in one variable with fractional coefficients
Question 33Question

The length LL, in centimeters, of a copper rod at a temperature of TT degrees Celsius can be modeled by the linear equation L=150.04+0.012TL = 150.04 + 0.012T. If the length of the rod is measured to be 150.40150.40 centimeters, what is its temperature in degrees Celsius?

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Answer: 30

Answer

The temperature of the rod is 30 degrees Celsius.
The correct answer is 30. By substituting the given length of 150.40150.40 centimeters into the equation for LL, we get 150.40=150.04+0.012T150.40 = 150.04 + 0.012T. Subtracting 150.04150.04 from both sides gives 0.36=0.012T0.36 = 0.012T. Finally, dividing both sides by 0.0120.012 yields the temperature T=30T = 30 degrees Celsius.

Step-by-Step Solution

1
Substitute the measured length L=150.40L = 150.40 into the equation.
150.40 = 150.04 + 0.012T
To set up the equation with the given value for length.
2
Subtract 150.04 from both sides of the equation.
0.36 = 0.012T
To isolate the variable term containing TT.
3
Divide both sides of the equation by 0.012.
T = 30
To find the temperature TT.

Key Concept

Solving a multi-step linear equation involving decimals
Question 34Question

A marketing firm charges a flat setup fee of 160160 plus 3.203.20 for each promotional brochure printed. For a large order, the firm applies a 15%15\% discount to the total cost (the sum of the setup fee and the printing cost). If the final discounted bill is 680680, how many brochures were printed?

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Answer: 200

Answer

200
The correct answer of 200 brochures is found by formulating the equation 0.85(160+3.2b)=6800.85(160 + 3.2b) = 680. Dividing both sides by 0.850.85 yields 160+3.2b=800160 + 3.2b = 800. Subtracting 160160 gives 3.2b=6403.2b = 640, and dividing by 3.23.2 results in b=200b = 200.

Step-by-Step Solution

1
Translate the word problem into a linear equation where bb represents the number of brochures. The total cost before discount is 160+3.2b160 + 3.2b. Applying a 15%15\% discount means paying 85%85\% of this total.
0.85(160+3.2b)=6800.85(160 + 3.2b) = 680
This sets up the relationship between the total discounted bill and the number of brochures.
2
Divide both sides of the equation by 0.850.85 to isolate the expression within parentheses.
160+3.2b=800160 + 3.2b = 800
Dividing by 0.850.85 simplifies the equation by calculating the total cost before the discount was applied.
3
Subtract 160160 from both sides to isolate the term containing the variable bb.
3.2b=6403.2b = 640
Subtracting the flat setup fee isolates the printing cost of the brochures.
4
Divide both sides by 3.23.2 to solve for bb.
b=200b = 200
Dividing by the per-brochure printing cost yields the total number of brochures printed.

Key Concept

Solving multi-step linear equations involving percentage discounts and decimal coefficients.

Alternative Method

Instead of dividing by 0.850.85 first, you can distribute 0.850.85 to both terms inside the parentheses to get 136+2.72b=680136 + 2.72b = 680. Subtract 136136 from both sides to get 2.72b=5442.72b = 544, then divide by 2.722.72 to find b=200b = 200.
Estimated Time:1m 30s
Question 35Question

If xx is a real number that satisfies the equation 35(2x7)+0.4=0.2(x+3)\frac{3}{5}(2x - 7) + 0.4 = 0.2(x + 3), what is the value of 5x25x - 2?

Show answer & explanation

Answer: 20

Answer

The value of the expression 5x25x - 2 is 2020.
First, convert the fraction 35\frac{3}{5} to the decimal 0.60.6. The equation becomes 0.6(2x7)+0.4=0.2(x+3)0.6(2x - 7) + 0.4 = 0.2(x + 3). Distribute on both sides to get 1.2x4.2+0.4=0.2x+0.61.2x - 4.2 + 0.4 = 0.2x + 0.6. Combine constant terms on the left side to get 1.2x3.8=0.2x+0.61.2x - 3.8 = 0.2x + 0.6. Subtract 0.2x0.2x and add 3.83.8 to both sides to isolate the variable, resulting in x=4.4x = 4.4. Finally, substitute x=4.4x = 4.4 into the expression 5x25x - 2 to get 5(4.4)2=222=205(4.4) - 2 = 22 - 2 = 20.

Step-by-Step Solution

1
Convert the fraction and distribute the coefficients
1.2x4.2+0.4=0.2x+0.61.2x - 4.2 + 0.4 = 0.2x + 0.6
To clear parentheses and align terms using decimals.
2
Combine constants on the left side
1.2x3.8=0.2x+0.61.2x - 3.8 = 0.2x + 0.6
To simplify the left-hand side of the linear equation.
3
Isolate the variable xx
x=4.4x = 4.4
To determine the value of the unknown variable.
4
Evaluate the target expression
2020
To compute the final value of the expression 5x25x - 2.

Key Concept

Solving linear equations with fractional and decimal coefficients
Question 36Question

A laboratory technician mixes two solutions. The volume of the first solution is represented by 12(x5)\frac{1}{2}(x - 5) liters, and the volume of the second solution is represented by 13(2x+1)\frac{1}{3}(2x + 1) liters, where xx is a positive real number. If the sum of the volumes of these two solutions is 66 liters, what is the value of 3x43x - 4?

Show answer & explanation

Answer: 1717

Answer

The value of the expression is 1717.
The sum of the volumes of the two solutions is 66 liters, which translates to the linear equation 12(x5)+13(2x+1)=6\frac{1}{2}(x - 5) + \frac{1}{3}(2x + 1) = 6. Multiplying the entire equation by the least common multiple of the denominators, 66, yields 3(x5)+2(2x+1)=363(x - 5) + 2(2x + 1) = 36. Distributing the constants leads to 3x15+4x+2=363x - 15 + 4x + 2 = 36. Combining like terms gives 7x13=367x - 13 = 36. Adding 1313 to both sides results in 7x=497x = 49, which gives x=7x = 7. Substituting x=7x = 7 into the expression 3x43x - 4 yields 3(7)4=173(7) - 4 = 17, which is the correct value.

Step-by-Step Solution

1
Set up the linear equation based on the word problem context.
12(x5)+13(2x+1)=6\frac{1}{2}(x - 5) + \frac{1}{3}(2x + 1) = 6
The sum of the volumes of the two solutions is given as 66 liters.
2
Clear the fractions by multiplying both sides of the equation by the least common multiple of the denominators.
3(x5)+2(2x+1)=363(x - 5) + 2(2x + 1) = 36
Multiplying by 66 eliminates the fractions and simplifies the equation for solving.
3
Distribute the coefficients to eliminate the parentheses.
3x15+4x+2=363x - 15 + 4x + 2 = 36
Applying the distributive property allows like terms to be grouped.
4
Combine like terms and isolate the variable xx.
7x13=36    7x=49    x=77x - 13 = 36 \implies 7x = 49 \implies x = 7
Adding 1313 to both sides and dividing by 77 solves for the value of the variable xx.
5
Evaluate the expression requested in the question using the solved value of xx.
3(7)4=214=173(7) - 4 = 21 - 4 = 17
Substituting x=7x = 7 into 3x43x - 4 yields the final requested value.

Key Concept

Solving linear equations with fractional coefficients by clearing denominators and evaluating variable expressions.

Alternative Method

Instead of clearing the fractions immediately, we can distribute the fractions first: 12x2.5+23x+13=6\frac{1}{2}x - 2.5 + \frac{2}{3}x + \frac{1}{3} = 6. Converting to fractions with a common denominator of 6, we get 36x156+46x+26=6\frac{3}{6}x - \frac{15}{6} + \frac{4}{6}x + \frac{2}{6} = 6, which simplifies to 76x136=6\frac{7}{6}x - \frac{13}{6} = 6. Adding 136\frac{13}{6} to both sides yields 76x=496\frac{7}{6}x = \frac{49}{6}, so 7x=497x = 49, and x=7x = 7. Substituting x=7x = 7 into the expression 3x43x - 4 yields 1717.
Estimated Time:1m 30s
Question 37Question

A business analyst uses the linear equation 25(3p10)1.2=0.4(p+5)\frac{2}{5}(3p - 10) - 1.2 = 0.4(p + 5) to estimate the equilibrium price pp, in dollars, of a new product. What is the equilibrium price, in dollars, of the product?

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Answer: 9

Answer

The equilibrium price of the product is 99 dollars.
Converting the fraction to a decimal gives 0.4(3p10)1.2=0.4(p+5)0.4(3p - 10) - 1.2 = 0.4(p + 5). Dividing both sides by 0.40.4 results in 3p103=p+53p - 10 - 3 = p + 5, which simplifies to 3p13=p+53p - 13 = p + 5. Subtracting pp and adding 1313 to both sides gives 2p=182p = 18, and dividing by 22 results in 99.

Step-by-Step Solution

1
Convert the fraction to decimal form
0.4(3p10)1.2=0.4(p+5)0.4(3p - 10) - 1.2 = 0.4(p + 5)
Converting 25\frac{2}{5} to 0.40.4 makes all terms decimals, simplifying further operations.
2
Divide both sides of the equation by 0.40.4
(3p10)3=p+5(3p - 10) - 3 = p + 5
Since 0.40.4 is a common factor and 1.2/0.4=31.2 / 0.4 = 3, dividing both sides by 0.40.4 simplifies the coefficients.
3
Simplify the left side of the equation
3p13=p+53p - 13 = p + 5
Combine the constant terms 10-10 and 3-3 to simplify the expression.
4
Isolate the variable terms on one side
2p=182p = 18
Subtract pp from both sides and add 1313 to both sides.
5
Solve for pp
p=9p = 9
Divide both sides by 22 to find the final value.

Key Concept

Solving Linear Equations
Question 38Question

A local coffee shop sells two types of coffee blends: House Blend and organic Reserve Blend. A bag of Reserve Blend costs 4.504.50 dollars less than three times the cost of a bag of House Blend. A customer purchases 33 bags of House Blend and 22 bags of Reserve Blend for a total of 54.0054.00 dollars, excluding tax. What is the cost, in dollars, of a bag of Reserve Blend?

Show answer & explanation

Answer: 16.50

Answer

The cost of a bag of Reserve Blend is 16.50 dollars.
The cost of a bag of Reserve Blend is 16.50 dollars. Let xx represent the cost of a bag of House Blend. A bag of Reserve Blend costs 3x4.503x - 4.50. Since the total cost for 33 bags of House Blend and 22 bags of Reserve Blend is 54.0054.00, we write the linear equation 3x+2(3x4.50)=543x + 2(3x - 4.50) = 54. Expanding the terms gives 3x+6x9=543x + 6x - 9 = 54, which simplifies to 9x9=549x - 9 = 54. Adding 99 to both sides yields 9x=639x = 63. Dividing by 99 gives x=7.00x = 7.00. Substituting 7.007.00 back into the Reserve Blend expression yields 3(7.00)4.50=16.503(7.00) - 4.50 = 16.50 dollars.

Step-by-Step Solution

1
Define variables for the costs of each blend.
Let xx represent the cost of a bag of House Blend in dollars. The cost of a bag of Reserve Blend is represented by the expression 3x4.503x - 4.50.
Establishing algebraic expressions for the unknowns based on the problem description allows us to set up a linear equation.
2
Set up the linear equation based on the total cost of the purchase.
The total cost of 33 bags of House Blend and 22 bags of Reserve Blend is 54.0054.00 dollars: 3(x)+2(3x4.50)=543(x) + 2(3x - 4.50) = 54.
The sum of the individual total costs of the two blends must equal the overall purchase total.
3
Distribute and combine like terms to simplify the equation.
3x+6x9=543x + 6x - 9 = 54 simplifies to 9x9=549x - 9 = 54.
Applying the distributive property removes the parentheses, allowing like terms to be combined.
4
Isolate the variable term by adding 99 to both sides.
9x=639x = 63.
To solve for xx, we must first isolate the term containing the variable by performing the inverse operation.
5
Solve for xx by dividing both sides by 99.
x=7.00x = 7.00.
Dividing isolates xx, giving the cost of a bag of House Blend.
6
Calculate the cost of a bag of Reserve Blend using the expression from Step 1.
3(7.00)4.50=21.004.50=16.503(7.00) - 4.50 = 21.00 - 4.50 = 16.50 dollars.
The question asks for the cost of a bag of Reserve Blend, not the House Blend, so we evaluate the expression 3x4.503x - 4.50 at x=7.00x = 7.00.

Key Concept

Setting up and solving a single-variable linear equation to solve a real-world word problem with multiple unknown quantities.
Estimated Time:1m 30s
Question 39Question

A shipping company charges a rate based on the weight of a package. The total cost CC, in dollars, to ship a package of weight ww pounds is given by the formula C=58(w2)+6.50C = \frac{5}{8}(w - 2) + 6.50 for packages weighing more than 22 pounds. If the shipping cost for a certain package is $14.00\$14.00, what is the weight of the package, in pounds?

Show answer & explanation

Answer: 14

Answer

The weight of the package is 14 pounds.
Substituting C=14.00C = 14.00 into the formula gives 14.00=58(w2)+6.5014.00 = \frac{5}{8}(w - 2) + 6.50. Subtracting 6.506.50 from both sides yields 7.50=58(w2)7.50 = \frac{5}{8}(w - 2). Multiplying both sides by the reciprocal 85\frac{8}{5} yields 12=w212 = w - 2. Finally, adding 22 to both sides gives the weight w=14w = 14 pounds.

Step-by-Step Solution

1
Substitute the total shipping cost into the formula.
14.00=58(w2)+6.5014.00 = \frac{5}{8}(w - 2) + 6.50
Since the shipping cost CC is given as 14.0014.00, we substitute this value into the formula to solve for the unknown weight ww.
2
Subtract 6.506.50 from both sides of the equation.
7.50=58(w2)7.50 = \frac{5}{8}(w - 2)
Subtracting 6.506.50 isolates the term containing the variable ww on the right side of the equation.
3
Multiply both sides of the equation by the reciprocal of the fraction.
12=w212 = w - 2
Multiplying by 85\frac{8}{5} eliminates the fractional coefficient of 58\frac{5}{8} on the right side.
4
Add 22 to both sides of the equation to solve for ww.
w=14w = 14
Adding 22 isolates the variable ww, giving the final weight of the package.

Key Concept

Solving linear equations with fractional and decimal terms
Estimated Time:1m 30s
Question 40Question

A craft cider company produces two specialty blends. The production cost, in dollars per gallon, of the premium blend is represented by the expression 34(d8)\frac{3}{4}(d - 8), where dd is the wholesale cost, in dollars, of a bushel of apples. The production cost, in dollars per gallon, of the dry blend is represented by the expression 0.2(2d+5)0.2(2d + 5). If the production cost per gallon is the same for both blends, what is this production cost, in dollars per gallon?

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Answer: 9

Answer

The production cost is 9 dollars per gallon.
The correct answer is the value obtained by setting the two cost expressions equal, solving for d=20d = 20, and then substituting d=20d = 20 back into either expression to find the cost of 99 dollars per gallon.

Step-by-Step Solution

1
Set the two production cost expressions equal to each other.
34(d8)=0.2(2d+5)\frac{3}{4}(d - 8) = 0.2(2d + 5)
The problem states that the production cost per gallon is the same for both blends, so their algebraic representations must be equal.
2
Express the decimal as a fraction and solve for dd.
15(d8)=4(2d+5)    15d120=8d+20    7d=140    d=2015(d - 8) = 4(2d + 5) \implies 15d - 120 = 8d + 20 \implies 7d = 140 \implies d = 20
Converting 0.20.2 to 15\frac{1}{5} allows us to clear fractions by multiplying both sides of the equation by the least common multiple of the denominators, which is 2020. We then distribute, isolate the variable terms, and solve for dd.
3
Substitute the value of dd back into either of the original cost expressions to find the production cost.
Cost=34(208)=34(12)=9\text{Cost} = \frac{3}{4}(20 - 8) = \frac{3}{4}(12) = 9
The question asks for the production cost per gallon, not the value of the variable dd. Substituting d=20d = 20 into the premium blend cost expression gives the final cost.

Key Concept

Solving linear equations involving fractions and decimals, and evaluating expressions using the solved variable value.

Alternative Method

Convert all numbers to decimals. The premium blend cost is 0.75(d8)=0.75d60.75(d - 8) = 0.75d - 6. The dry blend cost is 0.2(2d+5)=0.4d+10.2(2d + 5) = 0.4d + 1. Equating them gives 0.75d6=0.4d+1    0.35d=7    d=200.75d - 6 = 0.4d + 1 \implies 0.35d = 7 \implies d = 20. Then find the cost: 0.75(20)6=156=90.75(20) - 6 = 15 - 6 = 9 dollars.
Estimated Time:1m 30s
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