Integers, Absolute Value, and Number Lines

41 questions

Question 41Question

On a temperature monitor scale represented as a horizontal number line, sensor AA is positioned at coordinate 18-18 and sensor BB is positioned at coordinate 1414. A relay station CC is located on the line segment between sensor AA and sensor BB such that the distance from sensor AA to relay station CC is 34\frac{3}{4} of the total distance between sensor AA and sensor BB. What is the absolute value of the coordinate of relay station CC?

Show answer & explanation

Answer: 6

Answer

The absolute value of the coordinate of relay station CC is 66.
To find the distance between AA (18-18) and BB (1414), subtract 18-18 from 1414 to get 3232 units. Three-fourths of 3232 is 2424 units. Adding 2424 units to the starting coordinate 18-18 yields 66 as the coordinate for CC. The absolute value of 66 is 66.

Step-by-Step Solution

1
Calculate the total distance between coordinates 18-18 and 1414
Distance = 14(18)=14+18=32|14 - (-18)| = |14 + 18| = 32 units
The distance between two points on a number line is given by the absolute value of the difference of their coordinates.
2
Calculate the distance from sensor AA to relay station CC
Distance AC=34×32=24AC = \frac{3}{4} \times 32 = 24 units
Relay station CC is positioned 34\frac{3}{4} of the total distance away from AA towards BB.
3
Find the coordinate of relay station CC
Coordinate of C=18+24=6C = -18 + 24 = 6
Moving rightward from 18-18 by 2424 units gives the location of CC.
4
Evaluate the absolute value of the coordinate of CC
6=6|6| = 6
The problem asks for the absolute value of the coordinate of CC.

Key Concept

Distance on a number line and absolute value evaluation
Estimated Time:1m 15s
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