Question

Difficulty: MediumOhm's Law Calculations and Concepts

A marine communications transceiver utilizes a direct current (DC) bias network. A voltmeter connected across a fixed 2.5 kΩ2.5\text{ k}\Omega resistor measures a steady voltage drop of 15 V15\text{ V}. What is the current flowing through this resistor?

  1. A
    37.5 mA37.5\text{ mA}
  2. B
    167 mA167\text{ mA}
  3. 6 mA6\text{ mA}Answer
  4. D
    0.6 mA0.6\text{ mA}

Answer

The current flowing through the resistor is 6 mA6\text{ mA}.
According to Ohm's law, current equals voltage divided by resistance (I=V/RI = V / R). Dividing 15 V15\text{ V} by 2.5 kΩ2.5\text{ k}\Omega (2500 Ω2500\text{ }\Omega) yields 0.006 A0.006\text{ A}, which converts directly to 6 mA6\text{ mA}.

Step-by-Step Solution

1
Convert the given resistance from kilo-ohms to fundamental SI units (ohms).
R=2.5 kΩ=2.5×103 Ω=2500 ΩR = 2.5\text{ k}\Omega = 2.5 \times 10^3\text{ }\Omega = 2500\text{ }\Omega
Standard calculations in Ohm's law require values in fundamental units (volts, amperes, ohms).
2
Apply Ohm's law formula to solve for current (I=V/RI = V / R).
I=15 V2500 Ω=0.006 AI = \frac{15\text{ V}}{2500\text{ }\Omega} = 0.006\text{ A}
Current is directly proportional to voltage and inversely proportional to resistance.
3
Convert the resulting current from amperes to milliamperes.
0.006 A=0.006×1000 mA=6 mA0.006\text{ A} = 0.006 \times 1000\text{ mA} = 6\text{ mA}
Matching the standard unit formatting in electronic measurement options.

Key Concept

Ohm's Law expresses the fundamental relationship between voltage, current, and resistance in a DC circuit (I=V/RI = V / R).
Estimated Time:1m 0s
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