A naval technician inspects a solid aluminum component intended for an aircraft assembly. … — Armed Services Vocational Aptitude Battery (ASVAB)

A naval technician inspects a solid aluminum component intended for an aircraft assembly. The component has a mass of $162\text{ g}$ and the density of aluminum is $2.7\text{ g/cm}^3$ . What is the volume of the component in cubic centimeters ( $\text{cm}^3$ )?

Answer: 60 cm^3

Answer

The volume of the aluminum component is

60\text{ cm}^3

Density is defined by the formula

\rho = \frac{m}{V}

. Rearranging algebraically to solve for volume yields

V = \frac{m}{\rho}

. Substituting the given values:

V = \frac{162\text{ g}}{2.7\text{ g/cm}^3} = 60\text{ cm}^3

Step-by-Step Solution

Identify the relevant physical formula and isolate the unknown variable

\text{Volume} = \frac{\text{Mass}}{\text{Density}}

Density (

\rho

) is a characteristic physical property defined as mass per unit volume (

\rho = \frac{m}{V}

Substitute the measured mass and known density to calculate volume

\text{Volume} = \frac{162\text{ g}}{2.7\text{ g/cm}^3} = 60\text{ cm}^3

Dividing

162

2.7

gives

60

, with units simplifying to

\text{cm}^3

Key Concept

Density as a fundamental physical property relating mass and volume

Estimated Time:1m 0s

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