An industrial cleaning solvent requires a mixture of Chemical A and Chemical B in a ratio of by volume. If a worker uses milliliters of Chemical B, how many liters of the final cleaning solvent will be produced?
- A1050
- B0.75
- 1.05Answer
- D10.5
Answer
1.05
The correct answer accurately scales the mixture from parts to a total volume. Since the ratio of Chemical A to B is 5:2, there are 7 total parts in the mixture. Chemical B makes up 2 of these 7 parts. Setting up the proportion 2/7 = 300/x gives a total volume of 1050 mL. Converting this volume to liters by dividing by 1000 results in 1.05 liters.
Step-by-Step Solution
Key Concept
Direct proportions and unit conversions in part-to-whole relationships
Alternative Method
Instead of setting up a formal proportion, use the unitary method. If 2 parts represent 300 mL, then 1 part equals 150 mL (300 / 2). The total mixture requires 7 parts, so the total volume is 7 * 150 = 1050 mL. Converting to liters gives 1.05 L.
Estimated Time:1m 30s