A naval navigation team is evaluating different telemetry datasets. Match each statistical… — Armed Services Vocational Aptitude Battery (ASVAB)

A naval navigation team is evaluating different telemetry datasets. Match each statistical description to its correct calculated value.

The median of the unsorted frequency readings (in GHz): $11$ , $4$ , $15$ , $7$ , $18$ , and $9$ . $10$
The required fifth reading to achieve a target mean of $18$ dB, given previous readings of $14$ , $16$ , $20$ , and $18$ . $22$
The new mean if an outlier of $34$ is added to a dataset of $5$ previous readings whose sum is $50$ . $14$
The mode of the recorded pulse widths (in ms): $22$ , $15$ , $15$ , $22$ , $10$ , $15$ , and $28$ . $15$

Answer

The median is 10, the missing fifth reading is 22, the new mean is 14, and the mode is 15.

Each correct match applies the fundamental operations for finding the median of an even set, determining a missing value from a given mean, calculating a shifted mean, and identifying the mode.

Step-by-Step Solution

Calculate the median of the frequency readings.

Sorted order:

4, 7, 9, 11, 15, 18

. Median is

10

The median of an even-numbered dataset is the average of the two middle values after sorting.

Calculate the missing fifth reading.

Total required =

90

. Existing sum =

68

. Missing value =

22

To find a missing value for a target mean, multiply the target mean by the total number of items, then subtract the sum of existing items.

Calculate the new mean after adding an outlier.

New sum =

84

, new item count =

6

. New mean =

14

A mean shifts when a new value is introduced; both the total sum and the total count of items must be updated.

Identify the mode of the pulse widths.

The mode is

15

The mode is simply the value with the highest frequency of occurrence.

Key Concept

Measures of Central Tendency

Question

Answer

Step-by-Step Solution

Key Concept

Common Mistakes

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