Question

Difficulty: MediumSeries Circuits

An aircraft avionics system is powered by a 28 V28\text{ V} DC supply connected in series with three components: a 40 Ω40\ \Omega indicator lamp, a 70 Ω70\ \Omega current-limiting resistor, and a 30 Ω30\ \Omega monitoring resistor. What is the voltage drop across the 70 Ω70\ \Omega current-limiting resistor?

  1. A
    28 V28\text{ V}
  2. 14 V14\text{ V}Answer
  3. C
    8 V8\text{ V}
  4. D
    5.6 V5.6\text{ V}

Answer

14 V14\text{ V}
The correct answer is 14 V14\text{ V}. In a series circuit, total resistance equals the sum of the individual resistors: 40 Ω+70 Ω+30 Ω=140 Ω40\ \Omega + 70\ \Omega + 30\ \Omega = 140\ \Omega. The circuit current is I=28 V/140 Ω=0.2 AI = 28\text{ V} / 140\ \Omega = 0.2\text{ A}. Multiplying this current by the 70 Ω70\ \Omega resistance gives a voltage drop of 0.2 A×70 Ω=14 V0.2\text{ A} \times 70\ \Omega = 14\text{ V}.

Step-by-Step Solution

1
Calculate the total equivalent resistance (RtotalR_{\text{total}}) of the series circuit.
Rtotal=40 Ω+70 Ω+30 Ω=140 ΩR_{\text{total}} = 40\ \Omega + 70\ \Omega + 30\ \Omega = 140\ \Omega
In a series circuit, total resistance is the algebraic sum of all individual resistances.
2
Determine the common circuit current (II) using Ohm's Law.
I=VtotalRtotal=28 V140 Ω=0.2 AI = \frac{V_{\text{total}}}{R_{\text{total}}} = \frac{28\text{ V}}{140\ \Omega} = 0.2\text{ A}
Current remains constant through every component along a single series path.
3
Calculate the voltage drop across the 70 Ω70\ \Omega resistor (V70ΩV_{70\Omega}).
V70Ω=I×R=0.2 A×70 Ω=14 VV_{70\Omega} = I \times R = 0.2\text{ A} \times 70\ \Omega = 14\text{ V}
Applying Ohm's Law (V=I×RV = I \times R) to the specific component yields its proportional voltage drop.

Key Concept

Series Circuit Resistance and Voltage Division

Alternative Method

Use the voltage divider formula directly: V70Ω=28 V×(70 Ω40 Ω+70 Ω+30 Ω)=28 V×70140=28 V×0.5=14 VV_{70\Omega} = 28\text{ V} \times \left(\frac{70\ \Omega}{40\ \Omega + 70\ \Omega + 30\ \Omega}\right) = 28\text{ V} \times \frac{70}{140} = 28\text{ V} \times 0.5 = 14\text{ V}.
Estimated Time:1m 0s
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