Question

Difficulty: EasyFraction Addition and Subtraction in Context

Read the scenario and complete the sentence by providing the simplified fraction or decimal.

Answer:A mechanic has 78\frac{7}{8} of a quart of oil in a bottle. After using 14\frac{1}{4} of a quart to lubricate a machine part, there is 【5/8】 of a quart of oil remaining.

Answer

5/8
To find the remaining oil, we subtract the used amount, 14\frac{1}{4} of a quart, from the starting amount, 78\frac{7}{8} of a quart. First, we must convert 14\frac{1}{4} to an equivalent fraction with a common denominator of 88. Since 4×2=84 \times 2 = 8, we multiply both the numerator and denominator by 22 to get 28\frac{2}{8}. Finally, we subtract the numerators while keeping the denominator the same: 78−28=58\frac{7}{8} - \frac{2}{8} = \frac{5}{8}.

Step-by-Step Solution

1
Identify the mathematical operation required.
Subtraction is needed.
The problem asks for the amount remaining after a specific portion is used.
2
Find a common denominator for the fractions 78\frac{7}{8} and 14\frac{1}{4}.
The least common denominator is 8.
Fractions must have the same denominator to be added or subtracted.
3
Convert 14\frac{1}{4} into an equivalent fraction with a denominator of 8.
14=1×24×2=28\frac{1}{4} = \frac{1 \times 2}{4 \times 2} = \frac{2}{8}
Multiplying the numerator and denominator by the same value maintains the fraction's proportion.
4
Subtract the converted fraction from the initial amount.
78−28=58\frac{7}{8} - \frac{2}{8} = \frac{5}{8}
Subtract the numerators while keeping the common denominator.

Key Concept

Subtracting fractions with unlike denominators by first finding a common denominator in a real-world context.
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