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Difficulty: EasyDecimal Operations and Currency Word Problems

A base cafeteria sells a lunch combo for $6.45\$6.45. If a soldier buys 1010 combos for her unit and the order includes a fixed $3.50\$3.50 delivery fee, what is the total cost of the order?

  1. $68.00\$68.00Answer
  2. B
    $99.50\$99.50
  3. C
    $64.50\$64.50
  4. D
    $64.85\$64.85

Answer

The total cost of the order is $68.00\$68.00.
The total cost is calculated in two steps. First, find the subtotal for the meals by multiplying the individual cost by the quantity: 10×$6.45=$64.5010 \times \$6.45 = \$64.50. Next, add the one-time fixed delivery fee to this subtotal: $64.50+$3.50=$68.00\$64.50 + \$3.50 = \$68.00.

Step-by-Step Solution

1
Calculate the total cost of the 10 lunch combos.
10×$6.45=$64.5010 \times \$6.45 = \$64.50
Each combo costs $6.45\$6.45, so multiplying by the quantity gives the subtotal for the meals.
2
Add the fixed delivery fee to the subtotal.
$64.50+$3.50=$68.00\$64.50 + \$3.50 = \$68.00
The delivery fee is a one-time fixed charge that must be added to the subtotal to find the final cost.

Key Concept

Multiplying decimals by powers of 10 and accurately aligning decimals when adding currency amounts.
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Topics

Decimal Operations and Currency Word Problems

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