Question

Difficulty: EasyLevers and Fulcrums

A landscaper is using a wheelbarrow to move a 120-pound120\text{-pound} rock. The rock's center of gravity is positioned exactly 2 feet2\text{ feet} behind the wheel's axle, which acts as the fulcrum. The handles where the landscaper applies upward force are located 6 feet6\text{ feet} behind the wheel's axle. What upward lifting force must be applied at the handles to hold the wheelbarrow level?

  1. A
    20 pounds20\text{ pounds}
  2. 40 pounds40\text{ pounds}Answer
  3. C
    60 pounds60\text{ pounds}
  4. D
    360 pounds360\text{ pounds}

Answer

The correct lifting force is 40 pounds40\text{ pounds}.
The correct answer is derived by balancing the torques around the fulcrum. The rock exerts a downward torque of 120 pounds×2 feet=240 foot-pounds120\text{ pounds} \times 2\text{ feet} = 240\text{ foot-pounds}. To keep the wheelbarrow level, the landscaper must exert an equal and opposite torque. By dividing the required torque (240 foot-pounds240\text{ foot-pounds}) by the distance of the handles from the fulcrum (6 feet6\text{ feet}), we find that 40 pounds40\text{ pounds} of upward force is required.

Step-by-Step Solution

1
Identify the type of simple machine and the appropriate formula.
A wheelbarrow is a second-class lever. The principle of torque balance applies: Effort Force×Effort Arm=Load Force×Load Arm\text{Effort Force} \times \text{Effort Arm} = \text{Load Force} \times \text{Load Arm}.
To find the unknown force, we must set the rotational forces (torques) equal to each other.
2
Determine the values for the load, load arm, and effort arm from the problem.
Load Force=120 pounds\text{Load Force} = 120\text{ pounds}, Load Arm=2 feet\text{Load Arm} = 2\text{ feet}, and Effort Arm=6 feet\text{Effort Arm} = 6\text{ feet}.
Correctly identifying distances relative to the fulcrum (the wheel's axle) is critical for calculating torque.
3
Substitute the values into the torque equation and solve for the Effort Force.
Effort Force×6=120×2\text{Effort Force} \times 6 = 120 \times 2. Simplifying gives 6×Effort Force=2406 \times \text{Effort Force} = 240. Dividing both sides by 66 gives Effort Force=40 pounds\text{Effort Force} = 40\text{ pounds}.
This mathematically isolates the unknown variable to find the exact force required to balance the load.

Key Concept

Torque balance in a second-class lever dictates that the mechanical advantage is the ratio of the effort arm to the load arm.
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