Question

Difficulty: HardVoltage and Electromotive Force (EMF)

An electronics technician is analyzing how electromotive force (EMF) and terminal voltage behave across various operational states of a DC power source. Match each electrical condition on the left with its correct analytical relationship or physical description on the right.

  • Open-circuit cell voltageEquals the full internal electromotive force (E\mathcal{E}) because zero current produces no internal voltage drop (Ir=0I r = 0).
  • Loaded cell terminal voltageEquals the source electromotive force minus internal resistance drop (E−Ir\mathcal{E} - I r), resulting in a lower potential difference across terminals.
  • External battery charging voltageMust exceed the source electromotive force (E+Ir\mathcal{E} + I r) to reverse current direction into the positive terminal.
  • Fundamental definition of the voltRepresents one joule of energy transferred per coulomb of electric charge (1 V=1 J/C1\text{ V} = 1\text{ J/C}).

Answer

Open-circuit cell voltage matches the full internal electromotive force without internal drop; loaded cell terminal voltage matches the electromotive force minus internal resistance drop; external battery charging voltage matches the electromotive force plus internal resistance drop; and the fundamental definition of the volt matches one joule of energy per coulomb of charge.
Electromotive force (EMF, E\mathcal{E}) is the total energy per unit charge supplied by a source. Under no-load conditions (I=0I = 0), the terminal voltage equals EMF. When delivering current (I>0I > 0) to a load, internal resistance produces a drop (IrI r), lowering terminal voltage to E−Ir\mathcal{E} - I r. During charging, the external supply must exceed EMF by E+Ir\mathcal{E} + I r to force current inward. Fundamentally, one volt is defined as one joule of energy per coulomb of charge (1 V=1 J/C1\text{ V} = 1\text{ J/C}).

Step-by-Step Solution

1
Analyze open-circuit state for a DC voltage source
Terminal voltage equals internal electromotive force (V=EV = \mathcal{E})
When no current flows (I=0 AI = 0\text{ A}), no voltage is dropped across internal resistance (Ir=0 VI r = 0\text{ V}).
2
Evaluate terminal voltage during active discharge under load
Terminal voltage drops to V=E−IrV = \mathcal{E} - I r
Current passing through the battery's internal resistance consumes a portion of the source EMF.
3
Determine required external voltage for charging a cell
Applied charging voltage must be V=E+IrV = \mathcal{E} + I r
The charger must provide higher potential than the cell's EMF to drive current in reverse against internal resistance.
4
State the fundamental physical definition of potential difference and electromotive force
1 V=1 J/C1\text{ V} = 1\text{ J/C}
Voltage is defined as electrical potential energy (work in joules) per unit charge (coulombs).

Key Concept

Electromotive Force (EMF) vs. Terminal Voltage and Internal Resistance Relations
Estimated Time:1m 30s
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