Question

Difficulty: MediumParallel Circuits

A mobile radar tracking unit contains two heating elements connected in parallel across a common direct-current voltage rail. The primary heating element has a resistance of 18 Ω18\ \Omega, and the secondary heating element has a resistance of 9 Ω9\ \Omega. What is the total equivalent resistance of this circuit?

  1. A
    27 Ω27\ \Omega
  2. 6 Ω6\ \OmegaAnswer
  3. C
    13.5 Ω13.5\ \Omega
  4. D
    2 Ω2\ \Omega

Answer

The total equivalent resistance of the parallel circuit is 6 Ω6\ \Omega.
The equivalent resistance of parallel resistors is found using the formula 1Req=1R1+1R2\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} or the shortcut Req=R1×R2R1+R2R_{eq} = \frac{R_1 \times R_2}{R_1 + R_2}. Substituting 18 Ω18\ \Omega and 9 Ω9\ \Omega yields 18×918+9=16227=6 Ω\frac{18 \times 9}{18 + 9} = \frac{162}{27} = 6\ \Omega, which is properly less than the smallest branch resistance (9 Ω9\ \Omega).

Step-by-Step Solution

1
Identify the standard equivalent resistance relationship for two unequal parallel branches
1Req=1R1+1R2\frac{1}{R_{eq}} = \frac{1}{R_1} + \frac{1}{R_2} or Req=R1×R2R1+R2R_{eq} = \frac{R_1 \times R_2}{R_1 + R_2}
Parallel branches provide multiple paths for current, resulting in a total equivalent resistance that is always smaller than the lowest individual branch resistance.
2
Substitute the given resistances (R1=18 ΩR_1 = 18\ \Omega and R2=9 ΩR_2 = 9\ \Omega) into the product-over-sum formula
Req=18×918+9=16227R_{eq} = \frac{18 \times 9}{18 + 9} = \frac{162}{27}
Using the product-over-sum method allows direct calculation without converting to fractions with a common denominator.
3
Divide the product by the sum to determine the equivalent resistance
Req=6 ΩR_{eq} = 6\ \Omega
Simplifying 16227\frac{162}{27} yields the total opposition to current offered by the two parallel elements.

Key Concept

Total Equivalent Resistance of Unequal Parallel Branches
Estimated Time:1m 0s
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