Question

Difficulty: MediumRatios and Proportions

A commercial bakery prepares a special bread dough using flour, water, and sourdough starter in a ratio of 11:6:311:6:3 by weight. If a single batch uses 4242 pounds of water, what is the total weight of the dough for this batch, in pounds?

Answer: 140 / 140 pounds / 140 lbs / 140 lb

Answer

140
Since the water represents 66 parts of the ratio and weighs 4242 pounds, each part weighs exactly 77 pounds (42÷6=742 \div 6 = 7). The entire batch of dough is composed of 2020 total parts (1111 for flour + 66 for water + 33 for starter). Multiplying the 2020 total parts by the 77 pounds per part results in a total batch weight of 140140 pounds.

Step-by-Step Solution

1
Find the value of one part in the ratio.
42÷6=742 \div 6 = 7 pounds per part.
Water corresponds to 66 parts of the 11:6:311:6:3 ratio, and its total weight is 4242 pounds.
2
Calculate the total number of parts in the entire dough mixture.
11+6+3=2011 + 6 + 3 = 20 total parts.
The total weight is the sum of the parts for flour, water, and starter.
3
Multiply the total number of parts by the weight of a single part.
20×7=14020 \times 7 = 140 pounds.
Scaling the 2020 total parts by the 77 pounds per part gives the total weight of the batch.

Key Concept

Solving proportions by finding the unit rate of a single part and multiplying it by the total number of parts.
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