An electronics technician measures a potential difference of 3.5\text{ kV} across the seco… — Armed Services Vocational Aptitude Battery (ASVAB)

An electronics technician measures a potential difference of $3.5\text{ kV}$ across the secondary winding of an ignition transformer. What is this electromotive force expressed in volts ( $\text{V}$ )?

Answer: 3500 V

Answer

3,500 V

The prefix 'kilo-' (abbreviated as 'k') indicates a factor of

1{}000

. Therefore, an electromotive force of

3.5\text{ kV}

is equivalent to

3.5 \times 1{}000 = 3{}500\text{ V}

Step-by-Step Solution

Identify the standard metric prefix multiplier for kilo (k)

The prefix kilo represents a multiplier of

10^3

, or

1{}000

Electromotive force expressed with standard engineering prefixes must be converted using the appropriate power of ten.

Multiply the numerical value in kilovolts by 1,000

3.5 \times 1{}000 = 3{}500\text{ V}

To convert from a larger prefixed unit (kilovolts) to the base electrical unit (volts), multiply by

1{}000

Key Concept

Metric prefix conversion of electrical potential difference and electromotive force (EMF)

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