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Difficulty: EasyNewton's Second Law (F=ma)

A warehouse automated sorting system applies a constant net horizontal force of 200 N200 \text{ N} to a package with a mass of 50 kg50 \text{ kg}. What is the resulting acceleration of the package?

  1. 4 m/s24 \text{ m/s}^2Answer
  2. B
    0.25 m/s20.25 \text{ m/s}^2
  3. C
    40 m/s240 \text{ m/s}^2
  4. D
    10,000 m/s210,000 \text{ m/s}^2

Answer

The resulting acceleration of the package is 4 m/s24 \text{ m/s}^2.
According to Newton's Second Law (F=maF = ma), acceleration is calculated by dividing the applied net force by the object's mass. Dividing 200 N200 \text{ N} by 50 kg50 \text{ kg} correctly results in 4 m/s24 \text{ m/s}^2.

Step-by-Step Solution

1
Identify the known variables provided in the problem.
Net Force (FF) = 200 N200 \text{ N}; Mass (mm) = 50 kg50 \text{ kg}.
Correctly identifying the givens ensures the proper values are placed into the physics formula.
2
State Newton's Second Law of Motion and rearrange it to solve for acceleration.
The formula F=maF = ma becomes a=Fma = \frac{F}{m}.
The question asks for the resulting acceleration, so the formula must isolate aa.
3
Substitute the known values into the rearranged formula and calculate the result.
a=20050=4 m/s2a = \frac{200}{50} = 4 \text{ m/s}^2.
Executing the division yields the final acceleration value in standard metric units.

Key Concept

Newton's Second Law (F=maF = ma) demonstrates that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.
Estimated Time:30s
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Newton's Second Law (F=ma)

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